Question

Answer all question for brainliest

Answer 1

Answer:

4.

• this shows that the height of 13 year old females in one class is less variable than the other class.
• this means that the height of students in class with range 6 may vary from person to person while that in class with range 3 maybe clustered around one another.
• we're expected to see students of almost same height in class ,with range 3, more than the students in class with range 6.

5.

arranging the values in ascending order

2, 2, 4, 4, 4, 5, 6, 6, 6, 8, 8, 9

$mean = \frac{ sum \: of \: all \: observations}{total \: number \: of \: observations}$

$= \frac{2+2+4+4+4+5+6+6+6+8+8+9}{12}$

$= \frac{64}{12} \\ = \frac{16}{3}$

median = 1/ 2 [ n/2th term +{ (n/2)+ 1 }th term ]

for n is even

= 1/ 2 [ 6th + 7th term]

= 1/ 2 [5 + 6]

= 5.5

mode = value with highest frequency or the value that appears most frequently In a given set of data.

mode =4, 6

because both 4and 6 appear 3 times in the given set of data which is the highest frequency.

Answer 2

Answer:

Answer:

4.

this shows that the height of 13 year old females in one class is less variable than the other class.

this means that the height of students in class with range 6 may vary from person to person while that in class with range 3 maybe clustered around one another.

we're expected to see students of almost same height in class ,with range 3, more than the students in class with range 6.

5.

arranging the values in ascending order

2, 2, 4, 4, 4, 5, 6, 6, 6, 8, 8, 9

mean = \frac{ sum \: of \: all \: observations}{total \: number \: of \: observations}mean=

totalnumberofobservations

sumofallobservations

= \frac{2+2+4+4+4+5+6+6+6+8+8+9}{12} =

12

2+2+4+4+4+5+6+6+6+8+8+9

\begin{gathered} = \frac{64}{12} \\ = \frac{16}{3} \end{gathered}

=

12

64

=

3

16

median = 1/ 2 [ n/2th term +{ (n/2)+ 1 }th term ]

for n is even

= 1/ 2 [ 6th + 7th term]

= 1/ 2 [5 + 6]

= 5.5

mode = value with highest frequency or the value that appears most frequently In a given set of data.

mode =4, 6

because both 4and 6 appear 3 times in the given set of data which is the highest frequency.

Step-by-step explanation:

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