Answer:
Explanation:
<u>1) Data:</u>
a) M = ?
b) mass of solue = 17 g
c) solute: NH₃
d) V = 0.5o liter
<u>2) Formulae:</u>
a) number of moles, n = mass in grams / molar mass
b) M = n / V (in liters)
<u>3) Solution</u>
a) Molar mass of NH₃ = 17.03 g/mol
b) n = mass in grams / molar mass = 17 g / 17.03 g/mol = 0.998 mol NH₃
c) M = n / V (in liters) = 0.998 mol / 0.50 liter = 1.996 M
d) Round to the appropiate number of significant figures, 2: 2.0 M.
Answer: 2.0 M
Water can only be the solvent, never the solute is the statement about a solution that is correct.
- The solute is the substance that, in general, is found in less quantity and that dissolves in the mixture.
- The solvent, on the other hand, is the substance that usually appears in greater quantity and where the solute dissolves.
- The most usual thing is that the solvent is the substance that establishes the physical state of the solution.
- Water is considered a universal solvent, since it is the liquid that dissolves the most substances, a quality linked to its status as a “polar molecule”, this is due to its ability to form hydrogen bonds with other substances.
Solubility depends on the properties of a solvent that allow it to interact with a solute in a stronger way than the solvent particles do with each other.
In particular, the polar character of water makes it an excellent solvent for polar and ionic solutes, which are called hydrophilic.
Therefore, we can conclude that water can only be the solvent, never the solute is the statement about a solution that is correct.
Learn more here: brainly.com/question/2835889
A simile is a comparison using "as" or "like" and a metaphor is a comparison without using "like" or "as"
<span>There are a number of ways
to express concentration of a solution. This includes molarity. Molarity is
expressed as the number of moles of solute per volume of the solution. We do as follows:
Molarity = mol / L = 0.100 mol OH / L
0.100 mol OH / L ( .250 L ) ( 1 mol </span>Sr(OH)2 • 8 H2O / 2 mol OH ) ( 265.76 g / 1 mol ) = 3.322 g Sr(OH)2 • 8 H2O needed
