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skelet666 [1.2K]
3 years ago
6

Consider the following system at equilibrium where \Delta H° = 18.8 kJ, and Kc = 9.52×10-2, at 350 K.

Chemistry
1 answer:
slega [8]3 years ago
7 0

Answer:

1. C. remains the same.  2. C. is less than Kc.  3. B. run in the reverse direction to reestablish equilibrium. 4. A. increase.

Explanation:

At constant temperature, the equilibrium concentration has not effect on the equilibrium constant because the rate constants do not change with change in the concentrations or amounts of the reactants or products. Change in the concentration of one reactant or product causes the concentration of the others to change so as to maintain a constant value for the equilibrium constant. On the other hand, the reaction quotient is used to measure the relative amounts of reactants and products during a chemical reaction at any point in time. The value of the reaction quotient shows the direction of the chemical reaction.

Therefore, when 0.31 moles of CCl4(g) are removed from the equilibrium system at constant temperature:

1. the value of Kc remains the same

2. the value of Qc  is less than Kc

3.  the reaction must run in the reverse direction to reestablish equilibrium

4.  the concentration of CH_{4} will increase because product will be converted to reactants to reestablish equilibrium.

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Answer:

The quantity of heat required to melt all the ice at 0°C is 2.21 * 10⁶ J

Explanation:

Latent heat of fusion  is the heat absorbed by a unit mass of a given solid at its melting point that completely converts the solid to a liquid at the same temperature. Its unit is Joules/kg or Joules/g.

1 calorie = 4.184 Joules

Therefore , 80.0 cal/g = 80.0 cal/g * 4.184 J/cal = 334.72 J/g

1 g = 0.001 kg; Heat of fusion in J/kg = 334.72 J/g * 1g /0.001 kg = 3.35 * 10⁵ J/kg

Quantity of heat, Q = mass * latent heat of fusion of ice

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Quantity of heat required = 2.21 * 10⁶ J

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5 0
3 years ago
Use the rhombus to find the measure of the following angles m
Studentka2010 [4]

DA = 13, BW = 5, WC = 12, ∠ACD = 25°, ∠DAB = 50°, ∠ADC = 130°, ∠DBC = 65° and ∠BWC = 90° given that ABCD is a rhombus and DB = 10, BC = 13, ∠WAD = 25°. This can be obtained by understanding the properties of a rhombus.

<h3>What are the required values of sides and angles?</h3>

Here in the question it is given that,

  • ABCD is a rhombus
  • DB = 10, BC = 13, ∠WAD = 25°

We have to find the values of DA, BW, WC, ∠BAC, ∠ACD, ∠DAB, ∠ADC, ∠DBC, ∠BWC.

1) Since all the sides of the rhombus are equal, DA = 13

2) Since diagonals are perpendicular bisectors of each other, BW = 5

3) Since formula of diagonal is,

d₁ = √4a² - d₂,

here a = 13, d₂ = 10

d₁ = √4×13² - 10

d₁ = √676 - 10 = √576 = 24

Since diagonals are perpendicular bisectors of each other

WC = 24/2  ⇒ WC = 12

4) Since diagonals are angle bisectors at the corners, ∠BAC = 25°

5) Since diagonals are angle bisectors at the corners,

∠BAW = ∠DAW = 25° ⇒ ∠BAD =∠BAW + ∠DAW = 25° + 25° ⇒∠BAD = 50°

Since opposite angles of the rhombus are equal,

∠BAD = ∠BCD = 50° ⇒ ∠BCW = ∠DCW = 25°

⇒ ∠ACD = 25°

6) Since diagonals are angle bisectors at the corners,∠BAW = ∠DAW = 25° ⇒ ∠BAD =∠BAW + ∠DAW = 25° + 25° ⇒∠BAD = 50°

⇒ ∠DAB = 50°

7) Since adjacent angles are supplementary angles,

∠BAD + ∠ADC = 180° ⇒ 50° + ∠ADC = 180° ⇒ ∠ADC = 180° - 50° = 130°

⇒ ∠ADC = 130°

8) Since diagonals are angle bisectors at the corners,

∠DBC = 130°/2

⇒ ∠DBC = 65°

9) Since all the sides make an angle of 90° at the center,

⇒ ∠BWC = 90°

Hence DA = 13, BW = 5, WC = 12, ∠ACD = 25°, ∠DAB = 50°, ∠ADC = 130°, ∠DBC = 65° and ∠BWC = 90° given that ABCD is a rhombus and DB = 10, BC = 13, ∠WAD = 25°.

Learn more about rhombus here:

brainly.com/question/27870968

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