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3 years ago

13

A golf club hits a 0.04551 kg golf ball off a golf tee. The club is in contact with the ball for 0.020 s, and the force applied

by the club is 115 N. What is the speed of the ball as it leaves the tee

1 answer:

Juliette [100K]3 years ago

8 0

Answer:

v = 50.5 m/s

Explanation:

F = (m)(^v/^t)

115N = (0.04551kg)(v/(0.020s))

2,526.917161 m/s² = v/(0.020s)

v = 50.53834322 m/s

v = 50.5 m/s

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Mrs. Lynn's art class is making pencil holders out of soup cans. Each student is first covering a can with felt. What will the c

DochEvi [55]

Answer:

25.13 cm

Explanation:

Mrs. Lynn's art class is making pencil holders out of soup cans

These soup cans are definitely in cylindrical forms.

Each student is first covering a can with felt.

A felt is a type of material that is used for covering other objects. Here a felt is used to cover soup cans.

So if the diameter of the bottom of the can is 8 cm (i.e d = 8cm)

What will the circumference of the piece of felt need to be in order to cover the bottom of the can?

The felt will also take the circumference of a cylinder; and which is given by the expression

C = 2 πr

since diameter (d) = 8 cm

radius (r) = $\frac{d}{2}$

r = $\frac{8}{2}$

r = 4 cm

C = 2 × π × 4 cm

C = 2 × 3.142 × 4 cm

C = 25.13 cm

∴ the circumference of the piece of felt need to be 25.13 cm in order to cover the bottom of the can.

6 0

3 years ago

A special rocket can produce 7.66 ✕ 10^5 N of instantaneous thrust with an exhaust speed of 3.05 ✕ 103 m/s in vacuum. What mass

adelina 88 [10]

The mass of fuel the engine burn each second to produce a thrust of 7.66×10⁵ N is 2.5×10² kg/s.

<h3 /><h3>What is mass?</h3>

Mass can be defined as the quantity of matter contained in a body. The S.I unit of mass is kilogram(kg)

To calculate the mass the engine burns each seconds, we use the formula below.

Formual:

M = T/v............. Equation

Where:

M = Mass per seconds of the rocket
T = Thrust
v = Velocity

From the question,

Given:

T = 7.66×10⁵ N
v = 3.05×10³ m/s

Substitute these values into equation 1

M = (7.66×10⁵)/(3.05×10³)
M = 2.5×10² kg/s

Hence, the mass of fuel burned in each second is 2.5×10² kg/s.

Learn more about mass here: brainly.com/question/25121535

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8 0

1 year ago

An electric motor rotates 60 times per second if the alternating current source is 60 Hz. How many times will an electric motor

valentina_108 [34]

Answer:

180,000

Explanation:

Frequency is a quantity that is measured in Hertz [Hz] and it represents the number of rotations per second.

A motor with a frequency of 50 Hz will rotate 50 times per second.

Since we don't want to know how many times it rotates per second, but per hour. The first step is to find how many seconds there are in an hour and then multiply that amount by 50.

Seconds in an hour:

there are 60 seconds per minute, and 60 minutes per hour, thus there are

60*60 = <u>3,600 seconds in an hour</u>

We know that the motor will rotate 50 times per second so to find the number of rotations in 1 hour = 3,600 seconds we multiply:

50*3,600 = 180,000 rotations

8 0

3 years ago

A 3874-kg rollercoaster is brought to the top of a 42m hill in 40 seconds,then drops 28m before the next hill.

Ede4ka [16]

(a) The work required to get the coaster to the top of the first hill is 1,594,538.4 J.

(b) The power required to bring the train to the top of the first hill is 39,863.46 W.

(c) The energy lost when the coaster drops is 531,512.8 J.

(d) The left at the bottom is determined as 1,063,025.6 J.

<h3>Work done to bring the rollercoaster top of the hill</h3>

W = Fn x d = mgh

W = 3874 x 9.8 x 42

W = 1,594,538.4 J

<h3>Power dissipated in bringing the rollercoaster on top hill</h3>

P = Fv

P = Fd/t

P = W/t

P = 1,594,538.4 /40 = 39,863.46 W

<h3>Energy lost when the coaster drops</h3>

E = 1,594,538.4 - (3874 x 9.8 x 28)

E = 531,512.8 J

<h3>Energy left at the bottom</h3>

E = 3874 x 9.8 x 28 = 1,063,025.6 J

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6 0

2 years ago

Help me to solve it . It’s urgent

Artist 52 [7]

Answer: 0°

Explanation:

Step 1: Squaring the given equation and simplifying it

Let θ be the angle between a and b.

Given: a+b=c

Squaring on both sides:

... (a+b) . (a+b) = c.c

> |a|² + |b|² + 2(a.b) = |c|²

> |a|² + |b|² + 2|a| |b| cos 0 = |c|²

a.b = |a| |b| cos 0]

We are also given;

|a+|b| = |c|

Squaring above equation

> |a|² + |b|² + 2|a| |b| = |c|²

Step 2: Comparing the equations:

Comparing eq( insert: small n)(1) and (2)

We get, cos 0 = 1

> 0 = 0°

Final answer: 0°

[Reminders: every letters in here has an arrow above on it]

7 0

2 years ago