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3 years ago

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A golf club hits a 0.04551 kg golf ball off a golf tee. The club is in contact with the ball for 0.020 s, and the force applied

by the club is 115 N. What is the speed of the ball as it leaves the tee

1 answer:

Juliette [100K]3 years ago

8 0

Answer:

v = 50.5 m/s

Explanation:

F = (m)(^v/^t)

115N = (0.04551kg)(v/(0.020s))

2,526.917161 m/s² = v/(0.020s)

v = 50.53834322 m/s

v = 50.5 m/s

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3 years ago

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3 years ago

an electric device is plugged into a 110v wall socket. if the device consumes 500 w of power, what is the resistance of the devi

andreev551 [17]

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3 years ago