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vodka [1.7K]
3 years ago
15

What's the total resistance in a circuit that contains three 60 Ω resistors connected in series?

Physics
1 answer:
Natasha_Volkova [10]3 years ago
3 0
R1+R2+R3=R
R1=60
R2=60
R3=60
60+60+60=180ohm
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A student traveling at 8m/s on a bike has a mass of 182 KG and collides into a boulder and comes to a abrupt halt in 0.08 second
Delicious77 [7]
I hope this helps u !!

8 0
3 years ago
A weather balloon has a volume of 90.0 l when it is released from sea level. What
frozen [14]

The final atmospheric pressure is 5.19\cdot 10^4 Pa

Explanation:

Assuming that the temperature of the air does not change, we can use Boyle's law, which states that for a gas kept at constant temperature, the pressure of the gas is inversely proportional to its volume. In formula,

pV=const.

where

p is the gas pressure

V is the volume

The equation can also be rewritten as

p_1 V_1 = p_2 V_2

where in our problem we have:

p_1= 1.03\cdot 10^5 Pa is the initial pressure (the atmospheric pressure at sea level)

V_1 = 90.0 L is the initial volume

p_2 is the final pressure

V_2 = 175.0 L is the final volume

Solving the equation for p2, we find the final pressure:

p_2 = \frac{p_1 V_1}{V_2}=\frac{(1.01\cdot 10^5)(90.0)}{175.0}=5.19\cdot 10^4 Pa

Learn more about ideal gases:

brainly.com/question/9321544

brainly.com/question/7316997

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#LearnwithBrainly

3 0
3 years ago
If all blocks are the same density, are they all the same material?
schepotkina [342]
No they are not the same material because having the same density doesnt mean its the same material also they can have a different density and be the same material 
8 0
3 years ago
Read 2 more answers
Si un balón tiene una masa aproximada de 0.5 kg ¿con que fuerza hay que patearlo para imprimirle una aceleración de 1.5m/s2?
ExtremeBDS [4]

Answer:

translation

Explanation:

If a ball has an approximate mass of 0.5 kg, with what force must be kicked to give it an acceleration of 1.5m / s2?

8 0
3 years ago
A particle with charge − 2.74 × 10 − 6 C −2.74×10−6 C is released at rest in a region of constant, uniform electric field. Assum
s2008m [1.1K]

Answer:

241.7 s

Explanation:

We are given that

Charge of particle=q=-2.74\times 10^{-6} C

Kinetic energy of particle=K_E=6.65\times 10^{-10} J

Initial time=t_1=6.36 s

Final potential difference=V_2=0.351 V

We have to find the time t after that the particle is released and traveled through a potential difference 0.351 V.

We know that

qV=K.E

Using the formula

2.74\times 10^{-6}V_1=6.65\times 10^{-10} J

V_1=\frac{6.65\times 10^{-10}}{2.74\times 10^{-6}}=2.43\times 10^{-4} V

Initial voltage=V_1=2.43\times 10^{-4} V

\frac{\initial\;voltage}{final\;voltage}=(\frac{initial\;time}{final\;time})^2

Using the formula

\frac{V_1}{V_2}=(\frac{6.36}{t})^2

\frac{2.43\times 10^{-4}}{0.351}=\frac{(6.36)^2}{t^2}

t^2=\frac{(6.36)^2\times 0.351}{2.43\times 10^{-4}}

t=\sqrt{\frac{(6.36)^2\times 0.351}{2.43\times 10^{-4}}}

t=241.7 s

Hence, after 241.7 s the particle is released has it traveled through a potential difference of 0.351 V.

6 0
3 years ago
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