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just olya [345]

3 years ago

7

The melting point of ice is the same temperature as the of water.

2 answers:

umka2103 [35]3 years ago

8 0

Answer:

Answer is freezing point of water. The same melting point of ice is the same freezing point of water.

Travka [436]3 years ago

7 0

Answer:

Freezing point.

Explanation:

In the case of freezing point and melting point there is a same transition of matter. In this case, freezing point is defined as the, liquid is changing into solid and this process will occur at the same temperature when melting is occur means solid is change into liquid.

When water is freezing or melting any one can notice that its temperature will remain at 0°C throughout these processes whether ice is converting into liquid or liquid is converting into ice.

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Robin Hood wishes to split an arrow already in the bull's-eye of a target 40 m away.

tamaranim1 [39]

Answer:

5.843 m

Explanation:

suppose that the arrow leave the bow with a horizontal speed , towards he bull's eye.

lets consider that horizontal motion

distance = speed * time

time = 40/ 37 = 1.081 s

arrow doesnot have a initial vertical velocity component. but it has a vertical motion due to gravity , which may cause a miss of the target.

applying motion equation

(assume g = 10 m/s²)

$s=ut+\frac{1}{2}*gt^{2} \\= 0+\frac{1}{2}*10*1.081^{2}\\= 5.843 m$

Arrow misses the target by 5.843m ig the arrow us split horizontally

4 0

3 years ago

2. Which of the following is NOT true of work?

salantis [7]

Answer:

D

Explanation:

Work is not a vector but it is a scalar

3 0

2 years ago

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Determine the CM of a rod assuming its linear mass density λ (its mass per unit length) varies linearly from λ = λ0 at the left

Dahasolnce [82]

Answer:

$x_c= \dfrac{5}{9}L$

$I=\dfrac {7}{12}\lambda_ 0 L^3$

Explanation:

Here mass density of rod is varying so we have to use the concept of integration to find mass and location of center of mass.

At any distance x from point A mass density

$\lambda =\lambda_0+ \dfrac{2\lambda _o-\lambda _o}{L}x$

$\lambda =\lambda_0+ \dfrac{\lambda _o}{L}x$

Lets take element mass at distance x

dm =λ dx

mass moment of inertia

$dI=\lambda x^2dx$

So total moment of inertia

$I=\int_{0}^{L}\lambda x^2dx$

By putting the values

$I=\int_{0}^{L}\lambda_ ox+ \dfrac{\lambda _o}{L}x^3 dx$

By integrating above we can find that

$I=\dfrac {7}{12}\lambda_ 0 L^3$

Now to find location of center mass

$x_c = \dfrac{\int xdm}{dm}$

$x_c = \dfrac{\int_{0}^{L} \lambda_ 0(1+\dfrac{x}{L})xdx}{\int_{0}^{L} \lambda_0(1+\dfrac{x}{L})}$

Now by integrating the above

$x_c=\dfrac{\dfrac{L^2}{2}+\dfrac{L^3}{3L}}{L+\dfrac{L^2}{2L}}$

$x_c= \dfrac{5}{9}L$

So mass moment of inertia $I=\dfrac {7}{12}\lambda_ 0 L^3$ and location of center of mass $x_c= \dfrac{5}{9}L$

8 0

3 years ago

What is a rock that is full of tiny connected air spaces

Reptile [31]

The preamble rock is filled with air spaces

7 0

3 years ago

Earth is the only planet known to have _____.

postnew [5]

the answer is bioshere

4 0

3 years ago

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