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Serjik [45]
3 years ago
9

A typical nuclear power plant converts 0.01% of the mass of its fuel into energy through nuclear reactions. how much fuel would

be needed to power an average city for one day? express the mass of fuel needed in kilograms to two significant figures. view available hint(s)
Physics
1 answer:
Svetlanka [38]3 years ago
8 0
The fuel will be for all the city is 2,000 kilograms
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A 4 kg bird has 18 joules of kinetic energy and is rolling 3 m/s. find the mass ?
vovangra [49]
KE = half of mass times squared speed
18 = 0.5 * mass * (3m/s)^2
18 = 4.5 mass
mass = 18 / 4.5 = 4 kg

3 0
3 years ago
When light falls on objects, it interacts with them in different ways as shown in the images. What type of interaction is seen i
agasfer [191]

Answers with explanation

1)

Transmission

If all the light passes through a medium without any absorption then transmittance is 100%.

2)

Refraction

Refraction is the bending of a wave when it enters a medium where its speed is different and rays are again refracted when they leave that medium,

3)

Reflection

Reflected rays don't pass through the medium instead rays bounces off an object at an angle.

7 0
2 years ago
At the same instant that a 0.50-kg ball is dropped from 25m above Earth,? At the same instant that a 0.50-kg ball is dropped fro
fiasKO [112]
I hope it is clearly visible.. Velocity of the center of mass of 2-ball system is - 11.54m/s. Minus indicates, velocity direction is in downward direction.

6 0
3 years ago
Find the ratio of the final speed of the electron to the final speed of the hydrogen ion, assuming non-relativistic speeds. Take
KiRa [710]

Answer:

\frac{V_{e}}{V_{h}}=0.428*10^{2}

Explanation:

From conservation of energy states that

K_{i}+v_{i}=v_{f}+K_{f}\\ as\\K_{i}=0\\K_{f}=1/2mv^{2}\\ v_{i}=qv\\v_{f}=0\\So\\qv=1/2mv^{2}\\ v=\sqrt{\frac{2qv}{m} }\\ Velocity_{electron}=\sqrt{\frac{2qv}{m_{e}} }\\Velocity_{hydrogen}=\sqrt{\frac{2qv}{m_{h}} }\\\frac{V_{e}}{V_{h}}=\sqrt{\frac{\frac{2qv}{m_{e}}}{\frac{2qv}{m_{h}}}}\\\frac{V_{e}}{V_{h}}=\sqrt{\frac{m_{h}}{m_{e}} }\\\frac{V_{e}}{V_{h}}=\sqrt{\frac{1.67*10^{-27} }{9.11*10^{-31} } }\\\frac{V_{e}}{V_{h}}=0.428*10^{2}

5 0
3 years ago
Small paragraph explaining how how potential and kinetic energy are related
weeeeeb [17]

Answer:

Kinetic energy is energy possessed by a body by virtue of its movement. Potential energy is the energy possessed by a body by virtue of its position or state. While kinetic energy of an object is relative to the state of other objects in its environment, potential energy is completely independent of its environment.

Explanation:

4 0
3 years ago
Read 2 more answers
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