PLEASE SOMEONE HELP ASAP

You have been asked to design a rectangular box with a square base and an open top. The volume of the box must be 1536cm3. Deter

Katen [24]

Answer:

The dimensions of the box are:

Length = 11.53cm

Breadth = 11.53cm

Height = 11.53cm

Step-by-step explanation:

The volume of the box can be calculated with this formula:

The volume of the box = area of square base X height of the box.

We are given that the length of one side of the square base is = x cm, and its height is h cm.

Area of square base = $x^{2}cm^{2}$

The surface area of the box will be minimized if the height of the box, is the same as its length. hence, we can take the height of the box to be x cm also.

In this case, the volume of the box will be $x^{3}=1536cm^{3}$

from this, $x =3\sqrt{1536}= 11.53cm$

There fore, the box has its length, height, and width all having the same values.

The dimensions of the box are:

Length = 11.53cm

Breadth = 11.53cm

Height = 11.53cm

8 0

3 years ago

Determining Exponential Growth and Decay in Exercise, use the given information to write an exponential equation for y. Does the

frozen [14]

Answer:

$y = Ke^{5.2t}$

Exponential growth

Step-by-step explanation:

We can solve this differential equation by the separation of variables method.

We have that:

$\frac{dy}{dt} = 5.2y$

So

$\frac{dy}{y} = 5.2dt$

Integrating both sides

$\ln{y} = 5.2t + K$

In which K is the value of y when t = 0.

We apply the exponential to both sides, so:

$y = Ke^{5.2t}$

This is our exponential equation. Since the power of e is a positive value, the function represents exponential growth.

6 0

3 years ago

The height of a triangle is 3cm less than twice the base. The area is 10cm2

Kamila [148]

Answer:

The base is 4cm and the height is 5cm.

Step-by-step explanation:

This is a solve the system question. Call H the height of the triangle and B the base. The question tells us:

$H=2B-3$

and

$\frac{B \times H}{2}=10$

Sub the first equation into the second (as H is already isolated). You will end up with a quadratic equation - solve that any way you wish (e.g. quadratic formula). I've provided the factored form below which shows you the roots:

$\frac{B(2B-3)}{2}=10\\\frac{2B^2-3B}{2}=10\\2B^2-3B=20\\2B^2-3B-20=0\\(2B+5)(B-4)=0\\B= - \frac{5}{2},4$

In this question, we take B=4. You can't have a negative side length so the other answer is eliminated. Now sub the value for B into either of the original equations. I'll use the first, again because H is already isolated:

$H=2(4)-3\\H=8-3\\H=5$