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gregori [183]
3 years ago
10

(Middle school math) please help, thank you!

Mathematics
2 answers:
valentina_108 [34]3 years ago
7 0

Answer:

i dont know

Step-by-step explanation:

Veronika [31]3 years ago
7 0
I think it might be 8ft
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  • First question:

Recall that \cos^2x+\sin^2x=1 and \sqrt{x^2}=|x| for all x. So

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For 0, we expect both \cos x>0 and \sin x>0 (i.e. the sine and cosine of any angle that lies in the first quadrant must be positive). By definition of absolute value, |x|=x if x>0.

So we have

\dfrac{\sqrt{1-\cos^2x}}{\sin x}+\dfrac{\sqrt{1-\sin^2x}}{\cos x}=\dfrac{\sin x}{\sin x}+\dfrac{\cos x}{\cos x}=1+1=\boxed{2}

making H the answer.

  • Second question:

C is always true, because the inequality reduces to x > y.

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Oksi-84 [34.3K]
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In the figure given in attachment, AB and BC are two non common sides of ∠ABD and ∠DBC.

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Step-by-step explanation:

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