A 30 kg child rides a 20 kg bicycle. Together, the child and the bicycle have a momentum of 110 kg-m/s. What is the velocity of
1 answer:
Answer:
The velocity of the boy and the bicycle is 2.2 m/s.
Explanation:
We have,
Mass of child is 30 kg and the mass of bicycle is 20 kg. The combined momentum of the child and the bicycle is 110 kg-m/s.
It is required to find the velocity of the boy and the bicycle. The momentum of an object is given in terms of mass and its velocity. So,
M is combined mass of child and bicycle
So, the velocity of the boy and the bicycle is 2.2 m/s.
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This question can be solved using the concept of friction energy.
The thermal energy change is b "258.4 J".
The change in thermal energy will be equal to the friction energy produced during the motion of the box.
where,
μ = coefficient of kinetic friction = 0.4
f = force applied = 38 N
d = distance traveled by the box = 17 m
Therefore,
<u>E = 258.4 J</u>
Learn more about friction energy here:
Answer:
The bikers speed at the top of other hill is <u>25.82 m/s.</u>
Explanation:
Considering the biker is riding on a frictionless surface.
∴ There is no non-conservative or external force acting on the biker.
Hence we can conserve the energy of biker and bike as a system.
Let,
= 44m
= 10m
Since the biker starts from rest , his initial speed = 0 m/s
Let final speed of the bike at the top of other hill be .
∴ Initial Energy (at the top of 44m hill) =
Final Energy (at the top of 10m hill) = .
Conserving both the energies , we get
=
∴
Substituting the values for g , ,
, we get
= 25.82 m/s