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Serga [27]
3 years ago
14

21. An object appears blue when seen in sunlight. The same object is illuminated by a mixture of equally bright red and green li

ght. It is also viewed through a blue filter. What color does the object appear to be? A. Blue B. Cyan C. Black D. Green
Chemistry
1 answer:
faust18 [17]3 years ago
4 0

Answer: Green.

Explanation: Because object appears to be blue in sunlight, it absorbs counter colour of blue, also orange-red colour. So, when illuminated with

red-green colour, red light is more absorbed and object appears to be green.

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Compute the freezing point of this solution:
likoan [24]

Answer:

Freezing point = 1.25

Explanation:

If  we increase the concentration of the solution, the concentration of H+ does not change.

Convert 2.5% in to decimal

2.5%  = 2.5 ÷100

        = 0.025

The freezing point = 0.025 × 50

                               = 1.25

8 0
3 years ago
A sample of air was collected on a day when the total atmosphere pressure was
zhuklara [117]

Answer:

1. The gas law used: Dalton's law of partial pressure.

2. Pressure of nitrogen = 331 mmHg

Explanation:

From the question given above, the following data were obtained:

Total pressure (Pₜ) = 592 mmHg

Pressure of Oxygen (Pₒ) = 261 mmHg

Pressure of nitrogen (Pₙ) =?

The pressure of nitrogen in the sample can be obtained by using the Dalton's law of partial pressure. This is illustrated below:

Pₜ = Pₒ + Pₙ

592 = 261 + Pₙ

Collect like terms

592 – 261 = Pₙ

331 = Pₙ

Pₙ = 331 mmHg

Therefore, the pressure of nitrogen in the sample is 331 mmHg

5 0
3 years ago
What is the net ionic equation for this reaction? <br><br> FeCl3 + 3NaOH → Fe(OH)3 + 3NaCl
jok3333 [9.3K]

Answer:

2.6299

its easy

8 0
2 years ago
4) What volume will the gas in the balloon at right occupy at 250k?<br><br> balloon: 4.3L 350K
swat32

Answer:

2.87 liter.

Explanation:

Given:

Initially volume of balloon = 4.3 liter

Initially temperature of balloon = 350 K

Question asked:

What volume will the gas in the balloon occupy at 250 K ?

Solution:

By using:

Pv =nRT

Assuming pressure as constant,

V∝ T

Now, let  K is the constant.

V = KT

Let initial volume of balloon , V_{1} = 4.3 liter

1000 liter = 1 meter cube

1 liter = \frac{1}{1000} m^{3} = 10^{-3} m^{3

4.3 liter = 4.3\times10^{-3}=4.3\times10^{-3} m^{3}

And initial temperature of balloon, T_{1} = 350 K

Let the final volume of balloon is V_{2}

And as given, final temperature of balloon, T_{2} is 250 K

Now, V_{1} = KT_{1}

4.3\times10^{-3}=K\times350\ (equation\ 1 )

V_{2} = KT_{2}

=K\times250\ (equation 2)

Dividing equation 1 and 2,

\frac{4.3\times10^{-3}}{V_{2} } =\frac{K\times350}{K\times250}

K cancelled by K.

By cross multiplication:

350V_{2} =4.3\times10^{-3} \times250\\V_{2} =\frac{ 4.3\times10^{-3} \times250\\}{350} \\          = \frac{1075\times10^{-3}}{350} \\          =2.87\times10^{-3}m^{3}

Now, convert it into liter with the help of calculation done above,

2.87\times10^{-3} \times1000\\2.87\times10^{-3} \times10^{3} \\2.87\ liter

Therefore, volume of the gas in the balloon at 250 K will be  2.87 liter.

4 0
3 years ago
Assume that there is a puddle that contains 12.0 kg of water and it froze outside since it is -1°C. The
Musya8 [376]

The temperature that must be to freeze the solution would be -21.1 ° C.

<h3>How to calculate the freezing temperature of this solution?</h3>

To calculate the freezing temperature we must take into account the following information.

  • Solution with a salt concentration of 10% is frozen at -6°C
  • Solution with a salt concentration of 20% is frozen at -16°C
  • Solution with a higher concentration is frozen at -21.1°C

According to the above, it can be inferred that the puddle has a 50% concentration of salt because they had 12 kg of water and 6 kg of salt.

So the lowest freezing temperature would be 21.1°C because the puddle is 50% concentrated.

Note: This question is incomplete because there is some missing information. Here is the missing information:

  • A 10% salt solution freezes at about 20°F (-6°C), and a 20% solution freezes at 2°F (-16°C).
  • The lowest freezing point obtainable for salt solutions is −21.1 °C

Learn more about freezing in: brainly.com/question/14131507

4 0
2 years ago
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