Answer:
They're calibrated to measure, liquids of greatest density.
Explanation:
The power of the weightlifter is equal to the ratio between the work done by it and the time taken:
since we know the power and the time, we can find the work done:
For the work-energy theorem, this work done by the lifter is equal to the gravitational potential energy gained by the mass, which is given by:
where m is the mass and
is the increase in height. Rearranging the formula and using W=U, we can find the mass:
<span>uclear Physicist specializing inoffensive weapons systems - pretty obvious why this would be.
Highway Engineer - again, pretty obvious reasons.</span>
Answer:
correct answer is (c) 15 J
Explanation:
given data
mass m1 = 2 kg
velocity V1 = 5 m/s
mass other = 3 kg
so mass m2 = 2+ 3 kg = 5 kg
solution
we will apply here conservation of momentum:
m1V1 = m2V2 ..........................1
put here value and we get velocity v2
(2.0) × (5.0) = (2.0 + 3.0) × V
solve it we get
10 = 5 × V
2
V2 = 2.0 m/s
so here kinetic energy will be
KE = ½ × m × v²
so
∆KE = ½ × m1 × (v1)² - ½ × m2 × (v2)
²
∆KE = 0.5 × 2 × 25 - 0.5 × 5 × 4
∆KE = 25 - 10
∆KE = 15 J