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Answer:
81.85%
Step-by-step explanation:
Given :
The average summer temperature in Anchorage is 69°F.
The daily temperature is normally distributed with a standard deviation of 7°F .
To Find:What percentage of the time would the temperature be between 55°F and 76°F?
Solution:
Mean = 
Standard deviation = 
Formula : 
Now At x = 55


At x = 76


Now to find P(55<z<76)
P(2<z<-1)=P(z<2)-P(z>-1)
Using z table :
P(2<z<-1)=P(z<2)-P(z>-1)=0.9772-0.1587=0.8185
Now percentage of the time would the temperature be between 55°F and 76°F = 
Hence If the daily temperature is normally distributed with a standard deviation of 7°F, 81.85% of the time would the temperature be between 55°F and 76°F.
Basic method is Synthetic Division and Factor Theorem
Step-by-step explanation:
For higher-degree equations, the question becomes more complicated than others: cubic and quadratic equations can be solved by similar formulas.
Hence, to avoid those circumstances we can use Synthetic Division and Factor theorem to determine the squares of the given polynomial those who have order higher than 2.
Answer:
b. the ranges of penguin heights are the same.
Step-by-step explanation:
Hello!
Statements:
Which statement correctly compares the spreads of the distributions?
a. the mode of penguin heights at county side zoo is greater than the mode at city view zoo.
b. the ranges of penguin heights are the same.
c. the range of penguin heights is greater at city view zoo than at county side zoo.
d. the range of penguin heights is greater at county side zoo than at city view zoo.
The mode and mean are measurements of central tendency, these indicate the position of a data set but don't show any information concerning the distribution of said data.
The range on the other had is a measurement of variance, it shows the difference between the maximum and minimum values of the data set and indicates its total dispersion.
City view Zoo R= 44-37= 7 cm
County side Zoo: R= 45-38= 7 cm
Both ranges are the same.
I hope this helps!