The used work of energy output is 496*2.1=1041.6 J. And the actual work of energy output is 1127*0.85=957.95 J. The percentage efficiency is 957.95/1041.6*100%=91.97 %.
what is the final speed of the incoming ball if it is much more massive than the stationary ball? express your answer using two significant figures. v1 = 200 m / s submitprevious answers correct
Perfectly elastic collisions means that both mechanical energy and
momentum are conserved.
Therefore, for this case, we have the equation to find the final velocity of the incoming ball is given by
v1f = ((m1-m2) / (m1 + m2)) v1i
where,
v1i: initial speed of ball 1.
v1f: final speed of ball 1.
m1: mass of the ball 1
m2: mass of the ball 2
Since the mass of the ball 1 is much larger than the mass of the ball 2 m1 >> m2, then rewriting the equation:
v1f = ((m1) / (m1) v1i
v1f = v1i
v1f = 200 m / s
answer
200 m / s
part b part complete what is the final direction of the incoming ball with respect to the initial direction if it is much more massive than the stationary ball? forward submitprevious answers correct
Using the equation of part a, we can include in it the directions:
v1fx = ((m1-m2) / (m1 + m2)) v1ix
v1i: initial velocity of ball 1 in the direction of the x-axis
v1f: final speed of ball 1 in the direction of the x-axis
like m1 >> m2 then
v1fx = v1ix
v1fx = 200 m / s (positive x direction)
So it is concluded that the ball 1 continues forward.
answer:
forward
part c part complete what is the final speed of the stationary ball if the incoming ball is much more massive than the stationary ball ?.
The shock is perfectly elastic. For this case, we have that the equation to find the final velocity of the stationary ball is given by
v2f = ((2m1) / (m1 + m2)) v1i
where,
v1i: initial speed of ball 1.
v2f: final speed of ball 2.
m1: mass of the ball 1
m2: mass of the ball 2
Then, as we know that m1 >> m2 then
v2f = ((2m1) / (m1) v1i
v2f = 2 * v1i
v2f = 2 * (200 m / s)
v2f = 400 m / s
answer
400m / s
Answer:
The magnification would be "103.55". A further explanation is given below.
Explanation:
The given values are:
Distance between lens and eyepiece,
L = 85 cm
Eyepiece is,
= 123 D
Now,
The refractive power of eye piece will be:
⇒ 
The length of the telescope will be:
⇒ 
⇒ 
On substituting the values, we get
⇒ 
⇒ 
Now,
The magnification of the telescope will be:
⇒ 
⇒ 
⇒ 
Answer:
Explanation:
Given
frequency of wave 
We know velocity is given by
where 
=wavelength
The heat of fusion is the amount of energy required to change the state of one mole of substance from solid to liquid at constant temperature. Therefore, in order to determine the energy needed by a given mass of substance, we must first convert the mass into moles by using:
Moles = mass / Mr
Moles = 5.67 / 71.84
Moles = 0.079 mol
Energy = latent heat of fusion * moles
Energy = 32.2 * 0.079
Energy = 2.544 kJ = 2,544 J
