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GaryK [48]
3 years ago
8

A seesaw has an irregularly distributed mass of 30 kg, a length of 3.0 m, and a fulcrum beneath its midpoint. It is balanced whe

n a 60-kg person sits on one end and a 78-kg person sits on the other end.
Required:
Find a displacement of the center of mass of the system relatively to the seesaw's midpoint.
Physics
1 answer:
gladu [14]3 years ago
4 0

Answer:

x = 0.9 m

Explanation:

For this exercise we must use the rotational equilibrium relation, we will assume that the counterclockwise rotations are positive

          ∑ τ = 0

          60 1.5 - 78 1.5 + 30 x = 0

where x is measured from the left side of the fulcrum

           90 - 117 + 30 x = 0

           x = 27/30

           x = 0.9 m       

In summary the center of mass is on the side of the lightest weight x = 0.9 m

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mojhsa [17]

B. the distance the star is from Earth

Explanation:

The apparent magnitude of star is a function of its distance from the earth. It is one of the physical properties that is used to study a star.

The apparent magnitude of a star or other astronomical bodies is a measure of their brightness as seen from a location on the earth.

The apparent magnitude of a star depends on:

  • Distance of the star from the location on earth.
  • luminosity of the star
  • the particles along the part of the star and earth that cuts off the light the earth receives.

learn more:

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5 0
4 years ago
2. Kevin works as a janitor, and he is pushing a fully-
dybincka [34]

The time taken for him to move the bin 6.5 m is 2.30 s.

The given parameters;

  • <em>weight of the load, w = 557 N</em>
  • <em>force applied , F = 410 N</em>
  • <em>angle of force, =  15°</em>
  • <em>coefficient of kinetic friction  = 0.46</em>
  • <em>distance moved, d = 6.5 m</em>

The net horizontal force on the recycling bin is calculated as follows;

Fcos\theta - F_k = ma

where;

  • <em>m is the mass of the recycling bin</em>
  • <em />F_k<em> is the frictional force </em>

W = mg

557 = 9.8m\\\\m = \frac{557}{9.8} \\\\m = 56.84 \ kg

The net horizontal force on the recycling bin is calculated as;

Fcos \theta - F_k = ma\\\\Fcos\theta - \mu_kF_n  = ma\\\\410\times cos(15) \ - \ 0.46(557) = 56.84 a\\\\139.8 = 56.84a\\\\a = \frac{139.8}{56.84} \\\\a = 2.46 \ m/s^2

The time taken for him to move the bin 6.5 m is calculated as follows;

s = v_0t + \frac{1}{2} at^2\\\\6.5 = 0 + \frac{1}{2}  \times 2.46\times t^2\\\\6.5 = 1.23 t^2\\\\t^2 = \frac{6.5 }{1.23} \\\\t^2 = 5.285\\\\t = \sqrt{5.285} \\\\t = 2.30 \ s

Thus, the time taken for him to move the bin 6.5 m is 2.30 s.

Learn more here:brainly.com/question/21684583

7 0
3 years ago
Learning Goal:
enot [183]

Answer:

A. U_0 = \dfrac{\epsilon_0 A V^2}{2d}

B. U_1 = \dfrac{\epsilon_0 A V^2}{6d}

C. U_2 = \dfrac{K\epsilon_0 A V^2}{2d}

Explanation:

The capacitance of a capacitor is its ability to store charges. For parallel-plate capacitors, this ability depends the material between the plates, the common plate area and the plate separation. The relationship is

C=\dfrac{\epsilon A}{d}

C is the capacitance, A is the common plate area, d is the plate separation and \epsilon is the permittivity of the material between the plates.

For air or free space, \epsilon is \epsilon_0 called the permittivity of free space. In general, \epsilon=\epsilon_r \epsilon_0 where \epsilon_r is the relative permittivity or dielectric constant of the material between the plates. It is a factor that determines the strength of the material compared to air. In fact, for air or vacuum, \epsilon_r=1.

The energy stored in a capacitor is the average of the product of its charge and voltage.

U = \dfrac{QV}{2}

Its charge, Q, is related to its capacitance by Q=CV (this is the electrical definition of capacitance, a ratio of the charge to its voltage; the previous formula is the geometric definition). Substituting this in the formula for U,

U = \dfrac{CV^2}{2}

A. Substituting for C in U,

U_0 = \dfrac{\epsilon_0 A V^2}{2d}

B. When the distance is 3d,

U_1 = \dfrac{\epsilon_0 A V^2}{2\times3d}

U_1 = \dfrac{\epsilon_0 A V^2}{6d}

C. When the distance is restored but with a dielectric material of dielectric constant, K, inserted, we have

U_2 = \dfrac{K\epsilon_0 A V^2}{2d}

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3 years ago
What happens when a mechanical wave travels through a medium?
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3 0
3 years ago
Read 2 more answers
Who actually asked Abraham to sacrifice his son?
pochemuha

I think god did ??? I searched it up okay

7 0
2 years ago
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