1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
GaryK [48]
3 years ago
8

A seesaw has an irregularly distributed mass of 30 kg, a length of 3.0 m, and a fulcrum beneath its midpoint. It is balanced whe

n a 60-kg person sits on one end and a 78-kg person sits on the other end.
Required:
Find a displacement of the center of mass of the system relatively to the seesaw's midpoint.
Physics
1 answer:
gladu [14]3 years ago
4 0

Answer:

x = 0.9 m

Explanation:

For this exercise we must use the rotational equilibrium relation, we will assume that the counterclockwise rotations are positive

          ∑ τ = 0

          60 1.5 - 78 1.5 + 30 x = 0

where x is measured from the left side of the fulcrum

           90 - 117 + 30 x = 0

           x = 27/30

           x = 0.9 m       

In summary the center of mass is on the side of the lightest weight x = 0.9 m

You might be interested in
Explain the statement: “Cells are the basic units of structure and function in living things.”
babymother [125]

All living things are made up of cells.  Each cell's individual function helps the organism collectively function.  They are the most basic as they can be self-contained.  And there is no other particle smaller that can function on it's own.

6 0
3 years ago
24 A uniform electric field of magnitude 1.1×104 N/C is perpendicular to a square sheet with sides 2.0 m long. What is the elect
Tatiana [17]

Answer:

44,000 Nm^2/C

Explanation:

The electric flux through a certain surface is given by (for a uniform field):

\Phi = EA cos \theta

where:

E is the magnitude of the electric field

A is the area of the surface

\theta is the angle between the direction of the field and of the normal to the surface

In this problem, we have:

E=1.1\cdot 10^4 N/C is the electric field

L = 2.0 m is the side of the sheet, so the area is

A=L^2=(2.0)^2=4.0 m^2

\theta=0^{\circ}, since the electric field is perpendicular to the surface

Therefore, the electric flux is

\Phi =(1.1\cdot 10^4)(4.0)(cos 0^{\circ})=44,000 Nm^2/C

4 0
2 years ago
A student on her way to school walks eastward in a straight line 20.0 meters towards the bus stop, but realizes she dropped her
larisa [96]

Answer:

Total displacement will be 47 meter

Total distance will be 83 meters

Explanation:

We have given that first the student go eastward towards bus stop 20 meters

But he realizes that she dropped his physics notebook and so h=she turns back along the same way up to 18 meters

So displacement = 20-18 = 2 meters

And he travel 45 meters in east along the bus stop so total displacement = 45+2 = 47 meters

Total distance traveled by the student = 20+18+45 = 83 meters  

3 0
3 years ago
A 20 cm-radius ball is uniformly charged to 71 nC.
artcher [175]

Answer:

Part a)

\rho = 2.12\mu C/m^3

Part b)

q_1 = 1.11 nC

q_2 = 8.88 nC

q_3 = 71 nC

Part c)

E_1 = 3996 N/C

E_2 = 7992 N/C

E_3 = 15975 N/C

Explanation:

Part a)

As we know that charge density is the ratio of total charge and total volume

So here the volume of the charge ball is given as

V = \frac{4}{3}\pi R^3

V = \frac{4}{3}\pi(0.20)^3

V = 0.0335 m^3

now the charge density of the ball is given as

\rho = \frac{71 nC}{0.0335} = 2.12\mu C/m^3

Part b)

Now the charge enclosed by the surface is given as

q = \rho V

at radius of 5 cm

q = (2.12 \mu C/m^3)(\frac{4}{3}\pi(0.05)^3

q = 1.11 nC

at radius of 10 cm

q = (2.12 \mu C/m^3)(\frac{4}{3}\pi(0.10)^3

q = 8.88 nC

at radius of 20 cm

q = 71 nC

Part c)

As we know that electric field is given as

E = \frac{kq}{r^2}

so we have electric field at r = 5 cm

E_1 = \frac{(9\times 10^9)(1.11 nC)}{0.05^2}

E_1 = 3996 N/C

electric field at r = 10 cm

E_2 = \frac{(9\times 10^9)(8.88 nC)}{0.10^2}

E_2 = 7992 N/C

electric field at r = 20 cm

E_3 = \frac{(9\times 10^9)(71 nC)}{0.20^2}

E_3 = 15975 N/C

3 0
3 years ago
What is the weight of a person who has a mass of 76 kg?​
liq [111]

Answer:

<h2><em><u>7</u></em><em><u>4</u></em><em><u>4</u></em><em><u>.</u></em><em><u>8</u></em><em><u>N</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>answer </u></em><em><u>.</u></em><em><u> </u></em><em><u>Explanation</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>attachment </u></em><em><u>.</u></em></h2>

5 0
3 years ago
Other questions:
  • a teacher pushed a 10-kg desk across a floor for a distance of 5 m she exerted a horizontal force of 20 N how much work is done
    15·2 answers
  • What questions should be considered when evaluating the reliability of a website?
    5·2 answers
  • How does subjustion change the ocean florr<br><br> this is acctualy in science
    7·1 answer
  • What quantity do units represent in a value?
    8·2 answers
  • Elle is playing with a ball in a bus that moves in a straight line with constant velocity. What can you say about the motion of
    7·1 answer
  • which characteristic of good leadership is demonstrated when a president acknowledges that triumphs were done not for personal g
    5·2 answers
  • PLS HELP
    12·2 answers
  • Intensive properties can be: Select the correct answer below:
    8·1 answer
  • A vector has an x-component of 19.5m and a y-component of 28.4m. Find the magnitude and direction of the vector
    10·1 answer
  • ...
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!