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lara31 [8.8K]
2 years ago
10

If the domain of a function that is translated down 3 is (0, 4), (-5, 8), (4, -2), what is the range?

Mathematics
1 answer:
olga55 [171]2 years ago
7 0

Given:

The domain of function that is translated down 3 is (0, 4), (-5, 8), (4, -2).

To find:

The range of the function.

Solution:

If a function is translated 3 units down, then

(x,y)\to (x,y-3)

Using this rule, we get

(0,4)\to (0,4-3)

(0,4)\to (0,1)

Similarly,

(-5,8)\to (-5,5)

(4,-2)\to (4,-5)

The range of the given function is (0, 1), (-5, 5), (4, -5).

Therefore, the correct option is A.

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Answer:

The function will be: f(n) = 2n

Step-by-step explanation:

An arithmetic sequence is a sequence where the common difference between consecutive terms is same

The sequence according to given information is:

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Here

a_1 = 2

a_2 = 4

a_3 = 6

the common difference will be:

d = a_2-a_1 = 4-2 = 2\\d = a_3-a_2 = 6-4 = 2

The arithmetic sequence is given by:

a_n = a_1+(n-1)d

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Answer:

3/5

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There are 12 window seats and 8 aisle seats giving us a total of 20 seats.

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find the dimensions of the sports field at the right if the width is at least 60 yards AREA = 240 - 400X SQUARE YARDS
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Answer:

<u>The dimensions of the sports field are 80 yards and 3 - 5x yards</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Width of the sports field = At least 60 yards

Area of the sports field = 240 - 400x square yards

We can conclude the shape of the sports field is rectangular.

2. Find the dimensions of the sports field.

A. We need to find the Greatest Common factor between 240 and 400, this way:

The factors of 240 are: 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 16, 20, 24, 30, 40, 48, 60, 80, 120, 240 .

The factors of 400 are: 1, 2, 4, 5, 8, 10, 16, 20, 25, 40, 50, 80, 100, 200, 400 .

Then the greatest common factor is 80.

This GCF is also higher than 60, therefore it's one of the dimensions of the sports field.

Now, we calculate the other side of the sports, this way:

Second dimension of the sports field = (240 - 400x)/80

Second dimension of the sports field = 3 -5x

<u>The dimensions of the sports field are 80 yards and 3 - 5x yards</u>

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