Answer:7.229 grams of oxygen is formed by the complete reaction of 35.23 g of metallic sodium with oxygen at 130–200 °C, a process that generates sodium oxide, which in a separate stage absorbs oxygen: 4 Na + O2 → 2 Na2O. The ozone oxidizes the sodium to form sodium peroxide.
Answer: If I have 17 moles of gas at a temperature of 67°C, and a pressure of 5.34 atmospheres, what is the volume of the gas? write down all the givens of the problem
Answer:
https://zo-om.us/j/3349111797?pwd=V3F5NCtEQThCTGtCQ3VENlBIemx3dz09
take the dash out
Explanation:
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A pan on the stove getting hot, because the pan is conducting the heat from the stove.
1) Write the balanced chemical equation:
2Al + 6HCl ---> 2AlCl3 + 3H2
2) Calculate the molar masses of Al and HCl and use them to convert the data to moles
Al: 27g/mol => 10.7 gAl / 27g/mol = 0.396 mol Al
HCl: 1g/mol + 35.5 g/mol = 36.5g/mol => 42.5gHCl / 36.5g/mol = 1.164 mol HCl
Theoretical ratio: 6 mol HCl / 2 mol Al = 3:1
Actual ratio: 1.164 mol HCl / 0.396 mol Al = 2.94 : 1
Then there is a little bit less HCl than the predicted by theoretical ratio, which means that this is the limitant reagent.
3) Use the amount of HCl to make the calculations of the proucts obtained.
Theoretical ratio: 3 mol H2 / 6 mol HCl = 1:3
1.164 mol HCl * 1 mol H2 / 3 mol HCl = 0.388 mol H2
4) Use the ideal gas formula to obtain the volume
pV = n RT
p = 725 mmHg * 1atm / 760mmHg = 0.954 atm
n = 0.388 mol
R = 0.082 atm*liter /K*mol
T = 47 °C + 273.15 = 320.15K
V = nRT/p = 0.388 mol * 0.082 [atm*liter/K*mol] * 320.15K / 0.954 atm = 10.7 liter
Answer: 10.7 liter
