Carboxylic acid...........
Answer:
2HNO3+ Ba(OH)2 = Ba(NO3)2 + 2H2O
H3PO4 + Ca(OH)2 = Ca3(PO4)2 + 6H2O
Explanation:
2HNO3+ Ba(OH)2 = Ba(NO3)2 + 2H2O
H3PO4 + Ca(OH)2 = Ca3(PO4)2 + 6H2O
H+
O2-
OH-
Ba2+
Ca2+
NO3-
P 5+, 3+, 3-
H2O
Answer:
226.8 mg of mupirocin powder are required
Explanation:
Given that;
weight of standard pack = 22 g
mupirocin by weight = 2%
so weight of mupirocin = 2% × 22 = 2/100 × 22 = 0.44 g
so by adding the needed quantity of mupirocin powder to prepare a 3% w/w mupirocin ointment
mg of mupirocin powder are required = ?, lets rep this with x
Total weight of ointment = 22 + x g
Amount of mupirocin = 0.44 + x g
percentage of mupirocin in ointment is 3?
so
3/100 = 0.44 + x g / 22 + x g
3( 22 + x g ) = 100( 0.44 + x g )
66 + 3x g = 44 + 100x g
66 - 44 = 100x g - 3x g
97 x g = 22
x g = 22 / 97
x g = 0.2268 g
we know that; 1 gram = 1000 Milligram
so 0.2268 g = x mg
x mg = 0.2268 × 1000
x mg = 226.8 mg
Therefore, 226.8 mg of mupirocin powder are required