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MaRussiya [10]
2 years ago
9

An instructor wishes to determine the wavelength of the light in a laser beam. To do so, he directs the beam toward a partition

with two tiny slits separated by 0.195 mm. An interference pattern appears on a screen that lies 5.10 m from the slit pair. The instructor's measurements show that two adjacent bright interference fringes lie 1.55 cm apart on the screen. What is the laser's wavelength (in nm)
Physics
1 answer:
Morgarella [4.7K]2 years ago
5 0

Answer:

λ = 610.6 nm

Explanation:

We are given;

Separation distance; d = 0.195 mm = 0.195 × 10^(-3) m

Interference pattern distance; D = 4.95 m

Width of the two adjacent bright interference; β = 1.55 cm = 1.55 × 10^(-2) m

Formula for the Fringe width is;

β = Dλ/d

Where;

λ is laser's wavelength

Thus;

λ = (d × β)/(D)

λ = (0.195 × 10^(-3) × 1.55 × 10^(-2))/4.95

λ = 610.6 × 10^(-9) m

λ = 610.6 nm

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A bullet of mass 11 g strikes a ballistic pendulum of mass 1.9 kg. The center of mass of the pendulum rises a vertical distance
Ymorist [56]

Answer:

The bullet's initial speed is 243.21 m/s.

Explanation:

Given that,

Mass of the bullet, m_b=11\ g=0.011\ kg

Mass of the pendulum, m_p=19\ kg

The center of mass of the pendulum rises a vertical distance of 10 cm.

We need to find the bullet's initial speed if it is assumed that the bullet remains embedded in the pendulum. Let it is v. In this case, the energy of the system remains conserved. The kinetic energy of the bullet gets converted to potential energy for the whole system. So,

\dfrac{1}{2}(m_b+m_p)V^2 =(m_b+m_p)gh\\\\V=\sqrt{2gh} \ .................(1)

V is the speed of the bullet and pendulum at the time of collision

Now using conservation of momentum as :

m_bv=(m_p+m_b)V

Put the value of V from equation (1) in above equation as :

v=\dfrac{(m_p+m_b)}{m_b}\sqrt{2gh} \\\\v=\dfrac{(1.9+0.011)}{0.011}\sqrt{2\times 9.8\times 0.1}\\\\v=243.21\ m/s

So, the bullet's initial speed is 243.21 m/s.

7 0
3 years ago
Trumpeter A holds a B-flat note on the trumpet for a long time. Person C is running towards the trumpeter at a constant velocity
denpristay [2]

Answer:

Person B

Explanation:

Person B will hear the frequency that is lower than the B- flat.

5 0
3 years ago
Read 2 more answers
Work out the kinetic energy of a 2.5 kg remote-controlled car that is moving at 2 m/s.
lbvjy [14]

Answer: 5 joules

Explanation:

mass=m=2.5kg

Velocity=v=2m/s

Kinetic energy=ke

ke=(m x v x v)/2

ke=(2.5 x 2 x 2)/2

Ke=10/2

Ke=5

Kinetic energy=5 joules

8 0
3 years ago
While Newton's Second Law often deals with formulas and numerical calculations, there exist one very important nonnumerical conv
zheka24 [161]

Option B is the correct answer.

MKS system gives the following units:

Distance ----- meters

Mass ----- Kilograms

Time ----- seconds

meter is basic unit for length measurement. smaller units are centimeter, millimeter, micrometer, bigger units are kilometer and so on.

kilogram is the basic unit for mass. smaller unit is gram.

second is the basic unit for time. Greater units are minutes, hours, smallest unit are micro second and so on.

8 0
3 years ago
1. A 1,000-kg car has 50,000 joules of kinetic energy. What is its speed?
bulgar [2K]
Use KE= 1/2mv^2
So... 
50,000=(.5)(1,000)v^2
50,000=500 x v^2
Divide 500 on both sides 
100 = v^2 
Square root both sides to get rid of v^2 
Therefore v = 10 m/s
4 0
3 years ago
Read 2 more answers
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