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Nana76 [90]
3 years ago
9

Hey, guys need your help. I do school online and I have this project due. The problem is, I didn't know I needed most of these s

upplies till now. Can somebody please test this for me and give me a good explanation of what happened so I can understand what's going on? Thanks in advance! :)
Physics
1 answer:
Alexxandr [17]3 years ago
6 0
You need to post a picture so someone can help
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Where should clouds form and why
LiRa [457]

Answer:

When air rises in the atmosphere it gets cooler and is under less pressure. When air cools, it's not able to hold all of the water vapor it once was. Air also can't hold as much water when air pressure drops. The vapor becomes small water droplets or ice crystals and a cloud is formed.

Explanation:

hope this helps.

8 0
2 years ago
Two thin concentric spherical shells of radii r1 and r2 (r1 < r2) contain uniform surface charge densities V1 and V2, respect
Lyrx [107]

Answer:

Answer is explained in the explanation section below.

Explanation:

Solution:

We know that the Electric field inside the thin hollow shell is zero, if there is no charge inside it.

So,

a)  0 < r < r1 :

We know that the Electric field inside the thin hollow shell is zero, if there is no charge inside it.

Hence, E = 0 for r < r1

b)  r1 < r < r2:

Electric field =?

Let, us consider the Gaussian Surface,

E x 4 \pi r^{2}  = \frac{Q1}{E_{0} }

So,

Rearranging the above equation to get Electric field, we will get:

E = \frac{Q1}{E_{0} . 4 \pi. r^{2}   }

Multiply and divide by r1^{2}

E = \frac{Q1}{E_{0} . 4 \pi. r^{2}   } x \frac{r1^{2} }{r1^{2} }

Rearranging the above equation, we will get Electric Field for r1 < r < r2:

E= (σ1 x r1^{2}) /(E_{0} x r^{2})

c) r > r2 :

Electric Field = ?

E x 4 \pi r^{2}  = \frac{Q1 + Q2}{E_{0} }

Rearranging the above equation for E:

E = \frac{Q1+Q2}{E_{0} . 4 \pi. r^{2}   }

E = \frac{Q1}{E_{0} . 4 \pi. r^{2}   } + \frac{Q2}{E_{0} . 4 \pi. r^{2}   }

As we know from above, that:

\frac{Q1}{E_{0} . 4 \pi. r^{2}   } =  (σ1 x r1^{2}) /(E_{0} x r^{2})

Then, Similarly,

\frac{Q2}{E_{0} . 4 \pi. r^{2}   } = (σ2 x r2^{2}) /(E_{0} x r^{2})

So,

E = \frac{Q1}{E_{0} . 4 \pi. r^{2}   } + \frac{Q2}{E_{0} . 4 \pi. r^{2}   }

Replacing the above equations to get E:

E = (σ1 x r1^{2}) /(E_{0} x r^{2}) + (σ2 x r2^{2}) /(E_{0} x r^{2})

Now, for

d) Under what conditions,  E = 0, for r > r2?

For r > r2, E =0 if

σ1 x r1^{2} = - σ2 x r2^{2}

4 0
3 years ago
What are not some emotional reactions to stress?
ahrayia [7]
Any type of physical act isn’t a emotional reaction. Things like crying or yelling or getting mad at yourself is emotional. Changes in your activity level, change in eating, sleeping, sense of humor. Increased uses in tobacco or drugs, when you’re becoming accident prone, when you’re not able to relax, when your heart rate increases, headaches, startled easily, when you’re tired all the time and sleep doesn’t help (fatigue). For women your period might change. When you get lower back pain, upset stomach, flare ups that are associated with allergies asthma or arthritis and if you get sick easier. If you lose more hair than normal for your body. If you’re blood pressure is up. Things like this is physical. You might find people will isolate themselves or blame themselves. They may have a difficulty concentrating. You can look up so many ways that stress can affect a person physically
4 0
2 years ago
1.How far is Object Z from the origin at t = 3 seconds?
GenaCL600 [577]

Answer:

Please find the answer in the explanation

Explanation:

1.) How far is Object Z from the origin at t = 3 seconds

The distance of the object Z from the origin will be the slope of the graph.

Slope = 4/2 = 2m

2.) Which object takes the least time to reach a position 4 meters from the origin ?

According to the graph given to the question above, object Z has the list time which is 2 seconds since object X does not start from the origin.

3.) Which object is farthest from the origin at t = 2 seconds?

The correct answer is still object Z because it has the highest slope.

4 0
2 years ago
With an increase in temperature, the viscosity of liquids will: . (a) decrease (b) increase . (c) no change
ICE Princess25 [194]

Answer:

(a) decrease

Explanation:

Viscosity is the resistance which occur to flow of the fluid.

More the inter molecular forces between particles of the liquid, more the viscosity of liquid.

<u>Effect of temperature on viscosity:-</u>

Viscosity decreases with the increase in the temperature as forces among the particles decrease on increasing temperature. The kinetic energy of the particles of the liquid increases causing to move in more random motions and thus weaker inter molecular forces and this offer less resistance to the flow.

<u>Hence, viscosity of the liquids decrease with the increasing temperature.</u>

3 0
2 years ago
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