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Pavlova-9 [17]
3 years ago
6

In this lab you will need to prepare solutions using dilutions. Starting with the stock 0.300 M NaOH solution, how would you pre

pare a 0.100 M NaOH solution (using 0.300 M NaCl as the diluent)
Chemistry
1 answer:
tia_tia [17]3 years ago
4 0

Answer:

1/3 dilution : 1 volume of stock solution + 2 volumes of diluent

Explanation:

Concentrated solution = 0.300 NaOH

Diluted solution = 0.100 NaOH

The dilution factor is : 0.100/0.300 = 1/3

Thus, we have to dilute three times the stock solution. For this, we take 1 volume of stock solution and then we add 2 volumes of diluent. As result, we will have 1 volume of stock solution in a total of 3 volumes. For example, we take 1 mL of 0.300 NaOH and then we add 2 mL of diluent (0.300 NaCl). The final concentration after dilution will be:

Cd = 0.300 M x 1 mL/3 mL = 0.100 M

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Define the overvoltage in an electrolysis process​
monitta

Answer:

represents the additional driving force required to overcome barriers such as the large activation energy for the formation of a gas at a metal surface.

5 0
2 years ago
Identify the types of intermolecular forces present in each of the following substances, and select the substance in each pair t
Sergeu [11.5K]

Answer:

a. Van der Waals forces, C8H18 has higher boiling point.

b. Van der Waals forces in both compounds

    Dipole -Dipole in CH3OCH3

c. Van der Waals  and dipole-dipole in both, higher boiling point for  HOOH.

Additionally H bonding in HOOH

d. Van der Waals for both compounds,  additionally dipole- dipole and hydrogen bonding for  NH2NH2.

Higher boling point NH2NH2

Explanation:

To answer this question we have to know the hybridization of the atoms of interest and/or the presence of resultant dipole moments which make the molecule polar, and the van der Waals interactions. Also we have to look for the presence of hydrogen bonding.

Remember van der Waals forces will be present in all of the molecules since they are of the instantaneous type produced by the momentaneous distortions of the electron clouds.

a. These two compounds are hydrocarbons, the electronegativity difference between carbon and hydrogen is very small, so the only factor we need to consider are the van der Waals interactions.

The van der Waals interactions increase with molecular weight since they are interactions which are momentaneous between the atoms in the molecule, and the heavier the molecule the more these distortions are possible.

Since C8H18 has a higher molecular than C6H14, it follows it has a greater boiling point.

b. CH3OCH3  differs only on the added O atom to C3H8. They have similar molecular weights, 46 vs 44 g/mol, but the presence of the tehedral sp³ hybridized oxygen atom with its high electronegativity produces dipole moments and imparts a polarity to the molecule which make us to predict  CH3OCH3 will have a higher boiling point.

c.  In HOOH we have dipole-dipole moments since the oxygen atom is sp³ hybridized and the O-O-H is tetrahedral, the molecule is polar. Additionally we have the presence of H bond in this compound which is not possible in HSSH.

While the molecule HSSH is also polar since it has two dipole moments in the sp³ hybridized ( tetrahedral ) S,  it is not as big as the dipole moment in O-H.

Therefore Hydrogen peroxide, HOOH, has a higher boiling point than HSSH

d. The N-H bond has a dipole moment, and since the N is tetrahedral there is a resultant dipole moment. As in case d., we have hydrogen bonding  between H and N.

NH2NH2 then will have a higher boiling point than CH3CH3 where only van der Waals interactions are possible.

You are welcome.

8 0
4 years ago
HELP ME PLEASE: The image at the left shows three stars in the constellation Orion: Betelgeuse (A), Mintaka (B), and Rigel (C).
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Answer:A Betelgeuse

Explanation:

8 0
3 years ago
Read 2 more answers
Consider two acids: (ch3)3cco2h (pivalic acid, pka = 5.0) and hco2h (formic acid, pka = 3.8). Which acid is the stronger acid? S
Phoenix [80]
<h3>Answer:</h3>

            Formic acid is the stronger acid.

<h3>Explanation:</h3>

                   The strength of an acid is determined by the power of it to dissociate and produce H⁺ ions. Greater the dissociation of an acid, the stronger that acid is. Also, extent of dissociation for particular acid is given by its dissociation constant i.e. Ka.

The greater the Ka value, the stronger an acid is and vice versa.

Calculating Ka value of Pivalic acid:

As,

                                                 pKa  =  -log [Ka]

So,

                                                 Ka  =  10^-pKa

Putting value of pKa,

                                                 Ka  =  10⁻⁵

                                                Ka  =  1.0 × 10⁻⁵

Calculating Ka value of Formic acid:

As,

                                                 pKa  =  -log [Ka]

So,

                                                 Ka  =  10^-pKa

Putting value of pKa,

                                                 Ka  =  10⁻³'⁸

                                                 Ka  =  1.58 × 10⁻⁴

<h3>Conclusion:</h3>

                  As the Ka value of Formic acid is greater than Pivalic acid therefore, it is stronger acid than Pivalic acid.

<h2>TIP:</h2>

     When comparing strength of acids, the acid with the lowest pKa value is considered the strongest acid and <em>vice versa</em>.

8 0
3 years ago
What is in the cloud of negatively charged particles that surrounds an atom?
Zinaida [17]
Electrons. They make an electron cloud around the atom.
3 0
3 years ago
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