Answer: Several examples point to positive effects on the economy.
Explanation:
In the first place, it is possible to point out that environmental protection protects human health. This saves billions of dollars that could be spent on health issues. On the other hand, people employed in the sector pay taxes like all other citizens. On the other hand, they directly affect the environment. Vast sums of money would also be spent on cleaning these areas, so this organization acts preventively and saves money for the government.
Answer:
![\bf a)-v_2=220.11\;m/s](https://tex.z-dn.net/?f=%5Cbf%20a%29-v_2%3D220.11%5C%3Bm%2Fs)
![\bf b)-\sigma_{cv}=0.337\;kw/k](https://tex.z-dn.net/?f=%5Cbf%20b%29-%5Csigma_%7Bcv%7D%3D0.337%5C%3Bkw%2Fk)
Explanation:
a) - Taking enthalpy from the ideal air structure that is :
Given,
![T_1=52\° C](https://tex.z-dn.net/?f=T_1%3D52%5C%C2%B0%20C)
![Then,\;\;\;\;\;\; T_1=325 k](https://tex.z-dn.net/?f=Then%2C%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%20T_1%3D325%20k)
![And,\;\;\;\;\;\;\;\;h_1=325.31\; KJ/kg](https://tex.z-dn.net/?f=And%2C%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3Bh_1%3D325.31%5C%3B%20KJ%2Fkg)
![T_2=82^\circ C](https://tex.z-dn.net/?f=T_2%3D82%5E%5Ccirc%20C)
![Then,\;\;\;\;\;\; T_2=355 k](https://tex.z-dn.net/?f=Then%2C%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%20T_2%3D355%20k)
![And,\;\;\;\;\;\;\;\;h_2=355.535\; KJ/kg](https://tex.z-dn.net/?f=And%2C%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3Bh_2%3D355.535%5C%3B%20KJ%2Fkg)
Then, we have to apply the equation of the energy rate balance.
After applying that we have:
![m\left [\left (h_1-h_2 \right )+\frac{v_1^2-v_2^2}{2} \right ]=0](https://tex.z-dn.net/?f=m%5Cleft%20%5B%5Cleft%20%28h_1-h_2%20%5Cright%20%29%2B%5Cfrac%7Bv_1%5E2-v_2%5E2%7D%7B2%7D%20%5Cright%20%5D%3D0)
![\frac{v_1^2-v_2^2}{2} =h_2-h_1](https://tex.z-dn.net/?f=%5Cfrac%7Bv_1%5E2-v_2%5E2%7D%7B2%7D%20%3Dh_2-h_1)
![v_2^2=\left(V_1^2-2\right)\left(h_2-h_1\right)](https://tex.z-dn.net/?f=v_2%5E2%3D%5Cleft%28V_1%5E2-2%5Cright%29%5Cleft%28h_2-h_1%5Cright%29)
Then, we have to put values in the equation.
![v_2^2=\left(330^2\right)-2 \left(355.535-325.31\right)\times10^3](https://tex.z-dn.net/?f=v_2%5E2%3D%5Cleft%28330%5E2%5Cright%29-2%20%5Cleft%28355.535-325.31%5Cright%29%5Ctimes10%5E3)
![v_2=\sqrt{108900-60450}=220.11\;m/s](https://tex.z-dn.net/?f=v_2%3D%5Csqrt%7B108900-60450%7D%3D220.11%5C%3Bm%2Fs)
b) - Here, we have to apply the equation of the continuity.
![m=\frac{A_1V_1}{V_1}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7BA_1V_1%7D%7BV_1%7D)
![Then,\;\;\;\;\;\;\;\;\;\;\;=\frac{A_1V_1}{\frac{RT_1}{P_1} }](https://tex.z-dn.net/?f=Then%2C%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%3D%5Cfrac%7BA_1V_1%7D%7B%5Cfrac%7BRT_1%7D%7BP_1%7D%20%7D)
![=\frac{P_1}{RT_1} \times A_1V_1](https://tex.z-dn.net/?f=%3D%5Cfrac%7BP_1%7D%7BRT_1%7D%20%5Ctimes%20A_1V_1)
Then, we have to put values in the equation.
![=\frac{200\times 10^3}{287\left(52+273\right)} \times 16.57 \times 10^{-4}\times330=1.17\:kg/s](https://tex.z-dn.net/?f=%3D%5Cfrac%7B200%5Ctimes%2010%5E3%7D%7B287%5Cleft%2852%2B273%5Cright%29%7D%20%5Ctimes%2016.57%20%5Ctimes%2010%5E%7B-4%7D%5Ctimes330%3D1.17%5C%3Akg%2Fs)
Then, the values are :
![T_1=52^\circ C=325k](https://tex.z-dn.net/?f=T_1%3D52%5E%5Ccirc%20C%3D325k)
![S_1=1.78249\: KJ/s](https://tex.z-dn.net/?f=S_1%3D1.78249%5C%3A%20KJ%2Fs)
and,
![T_2=82^\circ C=355k](https://tex.z-dn.net/?f=T_2%3D82%5E%5Ccirc%20C%3D355k)
![S_2=1.871255\: KJ/s](https://tex.z-dn.net/?f=S_2%3D1.871255%5C%3A%20KJ%2Fs)
![\sigma_{cv}=m[S_2-S_1-R\;ln(\frac{P_2}{P_1}) ]](https://tex.z-dn.net/?f=%5Csigma_%7Bcv%7D%3Dm%5BS_2-S_1-R%5C%3Bln%28%5Cfrac%7BP_2%7D%7BP_1%7D%29%20%5D)
Then, we have to put values in the equation.
![=1.17\left[1.871255-1.78249-0.287\;ln\left(\frac{100}{200} \right)\right]](https://tex.z-dn.net/?f=%3D1.17%5Cleft%5B1.871255-1.78249-0.287%5C%3Bln%5Cleft%28%5Cfrac%7B100%7D%7B200%7D%20%5Cright%29%5Cright%5D)
![\sigma_{cv}=0.337\;KW/k](https://tex.z-dn.net/?f=%5Csigma_%7Bcv%7D%3D0.337%5C%3BKW%2Fk)
18.14% of the bags contains less than 22 kg
<h3>What is
z score?</h3>
Z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:
z = (raw score - mean) / standard deviation
Given that:
Mean = 22.73 kg, standard deviation = 0.80 kg
a) For <22:
z = (22 - 22.73)/0.8 = -0.91
P(z < -0.91) = 0.1814
18.14% of the bags contains less than 22 kg
Find out more on z score at: brainly.com/question/25638875
Answer:
I have 72 baes just kidding I have 73 but they all don't love me
Answer: Outside an intersections
Explanation: