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4 years ago

How many grams of sodium chloride, NaCl, result from the reaction shown in the following equation, FeCl3 + 3NaOH

Chemistry

2 answers:

Vera_Pavlovna [14]4 years ago

8 0

Answer:

175.33 g.

Explanation:

The balanced equation of reaction is given below;

FeCl3 + 3NaOH ---------> Fe(OH)3 + 3NaCl.

From the balanced equation of reaction we can see that one mole of FeCl3 reacts with three moles of sodium hydroxide to produce 3 mole of sodium chloride,NaCl and one mole of Fe(OH)3.

To calculate for the number of grams we will be needing the molar mass of Sodium chloride.

Molar mass of sodium chloride,NaCl= 22.989769 + 35.453 = 58.442769 grams per mole. Approximately, 58.443 grams per mole.

Therefore, the number of moles,n= mass/ molar mass. Recall that we have three(3) moles of Sodium chloride as the product. Hence,

3 mol = mass(in grams)/ molar mass(in grams per mol).

==> 3 = mass(in grams)/ 58.443 (grams per mol).

===> Mass in grams = 58.443 (grams per mol) × 3 mol.

Mass in grams = 175.33 grams.

LUCKY_DIMON [66]4 years ago

7 0

175.5g
Cl(35.5) x 3 = 106.5
Na(23) x 3 = 69
106.5 + 69 = 175.5g

or

0g because sodium and chlorine are not chemically bonded.

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3 years ago

Magnesium has three naturally occurring isotopes with masses of 23.99 amuamu, 24.99 amuamu, and 25.98 amuamu and natural abundan

bonufazy [111]

Answer:

24.309 g/mol

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For the first isotope:

23.99 * (78.99/100) = 18.95 g/mol

For the second isotope:

24.99 * (10/100) = 2.499 g/mol

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4 years ago

Read 2 more answers

Vanillin (used to flavor vanilla ice cream and other foods) is the substance whose aroma the human nose detects in the smallest

balu736 [363]

Answer:

Cost to supply enough vanillin is $3.2\$$

Explanation:

Threshold limit of vanillin in air is $2.0\times 10^{-11}g$ per litre means there should be $2.0\times 10^{-11}g$ of vanillin in 1L of air to detect aroma of vanillin.

$1ft^{3}=28.32L$

So, $5.0\times 10^{7}ft^{3}=(5.0\times 10^{7}\times 28.32)L$

So amount of vanillin should be present to detect = $(2.0\times 10^{-11}\times 5.0\times 10^{7}\times 28.32)g$

As cost of 50 g vanillin is $112\$$ therefore cost of $(2.0\times 10^{-11}\times 5.0\times 10^{7}\times 28.32)g$ vanillin = $(2.0\times 10^{-11}\times 5.0\times 10^{7}\times 28.32\times 112)\$ = 3.2\$$

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3 years ago

What amount of oxygen contains 1.8 x 10^22

Ksenya-84 [330]

I believe you mean what amount of O2 contains 1.8 x 10^22 molecules.

Solution: Divide your number of molecules by the number of molecules in one mole (6.02 x l0^23)

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4 years ago

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Wewaii [24]

Answer:

The controlled variable of an experiment is the one thing that stays the same in an experiment.

Explanation:

An example would be : if I have two pennies, both dunked in water, but than I change one to be dunked in vinegar, the one dunked in water still is the constant or the controlled variable.

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