Answer: The balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air is 
.
Explanation:
When a substance tends to gain oxygen atom in a chemical reaction and loses hydrogen atom then it is called oxidation reaction.
For example, chemical equation for oxidation of methane is as follows.
Number of atoms present on reactant side are as follows.
Number of atoms present on product side are as follows.
To balance this equation, multiply 
by 2 on reactant side. Also, multiply 
by 2 on product side. Hence, the equation can be rewritten as follows.
Now, the number of atoms present on reactant side are as follows.
Number of atoms present on product side are as follows.
Since, the atoms present on both reactant and product side are equal. Therefore, this equation is now balanced.
Thus, we can conclude that balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air is .
Answer:
On this 40th anniversary of the moon landing, let's consider where these beliefs and urban legends come from.
Explanation:
im not sure.
Based on nuclear stability, the symbol for the most likely product nuclide obtained when nitrogen-13 undergoes decay is coming from the following equation:
₇N¹³ → Positron₊₁⁰ + ₆C¹³
So the correct answer will be ₆C¹³
Answer:
151 g/mol
Explanation:
When a nonvolatile substance is added to a solvent, the freezing point of the solvent is changed, which is called cryoscopy. When temperature change can be calculated by:
ΔT = Kf*W
Where Kf is the molal freezing point constant of the solvent and W is the molality of the solution.
For cyclohexane, Kf = 20.2 °C/molal, and the freezing point is 6.4 °C, so:
6.4 - 1.05 = 20.2 * W
20.2W = 5.35
W = 0.26485 molal
The molality is:
W = m1/m2*M1
Where m1 is the mass of the solute (in g), m2 is the mass of the solvent (in kg), and M1 is the molar mass of the solute. So:
0.26485 = 2.00/0.05M1
0.0132425M1 = 2.00
M1 = 151 g/mol
