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Alex777 [14]
3 years ago
15

Place the atomic models in order of their atomic discoveries.

Physics
1 answer:
MrRa [10]3 years ago
5 0

Answer/Explanation:

A timeline of atomic models

  • Atomic model (1808)
  • Plum-pudding model (1904)
  • Nuclear model (1911)
  • Planetary model (1913)
  • Quantum mechanical model (1926-present)

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What is the period of a wave with a speed of 20.0 m/s and a frequency of 10.0 Hz?
Delvig [45]

<em>im confused hold on imma send you a link to the answer</em>Explanation:

4 0
3 years ago
Two spheres having masses M and 2M and radii R and 3R, respectively, are released from rest when the distance between their cent
Andrei [34K]

Answer:

v_2 = \sqrt{\frac{GM}{3R}}

v_1 = 2\sqrt{\frac{GM}{3R}}

Explanation:

As we know by energy conservation that change in gravitational potential energy of the system = change in kinetic energy of the two ball

So here we can say

-\frac{GM(2M)}{12R} + 0 = -\frac{GM(2M)}{4R} + \frac{1}{2}Mv_1^2 + \frac{1}{2}(2M)v_2^2

Also since there is no external force on the system of two masses so here total momentum of the two balls will remains conserved

0 = Mv_1 + 2Mv_2

v_1 = -2v_2

now we have

\frac{GM^2}{2R} - \frac{GM^2}{6R} = \frac{1}{2}M(-2v_2)^2 + \frac{1}{2}(2M)v_2^2

\frac{GM^2}{3R} = Mv_2^2

v_2 = \sqrt{\frac{GM}{3R}}

v_1 = 2\sqrt{\frac{GM}{3R}}

4 0
4 years ago
Which of the following is a subatomic particle?
mr Goodwill [35]

Answer:

neutron.

Explanation:

subatomic particles include,

neutron.

proton.

electron.

hope it helps. :)

4 0
3 years ago
Plz help fast!!
barxatty [35]
We are asked to compare two series circuits having equal number of light bulbs.
1st circuit is powered by 6 batteries each having a voltage of 1.5V
2nd circuit is powered by a single battery having a voltage of 9V.
The six batteries in the 1st circuit can be connected together in series or in parallel.
When the batteries are connected in series (positive terminal of one battery connected to negative terminal of another battery) their voltage gets added which means
Voltage of pack = number of batteries*voltage of each battery
Voltage of pack = 6*1.5
Voltage of pack = 9 volts
But the current remains same in the series connection since there is only path for the current to flow.
On the other hand, when the batteries are connected in parallel, the voltage remains same but the current increases.
Circuit 1:
In this circuit, we have 6 batteries each of 1.5 volts connected in series to provide a voltage of 9 volts.
We have connected 2 bulbs in this series circuit.
The voltage will be equally divided between two bulbs if both bulbs are identical in construction.
So there will be 4.5 volts across each bulb and both bulbs will have same brightness.
Circuit 2:
In this circuit, we have 1 battery which provide a voltage of 9 volts.
We have connected 2 bulbs in this series circuit just like in circuit 1.
The voltage will be equally divided between two bulbs if both bulbs are identical in construction.
So there will be 4.5 volts across each bulb and both bulbs will have same brightness.
Conclusion:
Both series circuits provide a total voltage of 9 volts to the two bulbs connected in series and the voltage will be equally divided among two bulbs and they will have same brightness. Therefore, both circuits will have same characteristics.
5 0
4 years ago
Solenoid 2 has twice the radius and six times the number of turns per unit length as solenoid 1. The ratio of the magnetic field
Xelga [282]

Answer:

6

Explanation:

The magnetic field inside a solenoid is given by the following formula:

B = \mu_{0}nI

where,

B = Magnetic Field Inside Solenoid

μ₀ = permittivity of free space

n = No. of turns per unit length

I = Current Passing through Solenoid

For Solenoid 1:

B_{1} = \mu_{0}n_{1}I  ------------------- equation 1

For Solenoid 2:

n₂ = 6n₁

Therefore,

B_{1} = \mu_{0}n_{2}I\\B_{1} = 6\mu_{0}n_{1}I  ----------------- equation 2

Diving equation 1 and equation 2:

\frac{B_{2}}{B_{1}} = \frac{6\mu_{0}nI}{\mu_{0}nI}\\\\\frac{B_{2}}{B_{1}} = 6

Hence, the correct option is:

<u>6</u>

8 0
3 years ago
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