Answer:

Explanation:
We are asked to find the force being applied to a book. According to Newton's Second Law of Motion, force is the product of mass and acceleration.

The mass of the book is 0.75 kilograms and the acceleration is 0.3 meters per square second. Substitute these values into the formula.

Multiply.

1 kilogram meter per second squared is equal to 1 Newton. Therefore, our answer of 0.225 kilogram meters per second squared is equal to 0.225 Newtons.

<u>0.225 Newtons of force</u> are applied to the book.
Answer:
Speed =0.283m/ s
Direction = 47.86°
Explanation:
Since it is a two dimensional momentum question with pucks having the same mass, we derive the momentum in xy plane
MU1 =MU2cos38 + MV2cos y ...x plane
0 = MU2sin38 - MV2sin y .....y plane
Where M= mass of puck, U1 = initial velocity of puck 1=0.46, U2 = final velocity of puck 1 =0.34, V2 = final velocity of puck 2, y= angular direction of puck2
Substitute into equation above
.46 = .34cos38 + V2cos y ...equ1
.34sin38 = V2sin y...equ2
.19=V2cos Y...x
.21=V2sin Y ...y
From x
V2 =0.19/cost
Sub V2 into y
0.21 = 0.19(Sin y/cos y)
1.1052 = tan y
y = 47.86°
Sub Y in to x plane equ
.19 = V2 cos 47.86°
V2=0.283m/s
1212.54 is what 550 kgs is equal to the weight of the car
The ramp has dimensions of 20 m length and 4 m height. The angle made by the ramp on the horizontal ground is
θ = sin⁻¹ (4/20)
After getting the angle, the force required to move the box can then be solved given that the mass of the box is known and also the coefficient of friction of the ramp