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It must be noted that during an elastic collision both the momentum and kinetic energy are conserved. For the kinetic energy, it can be solved through the equation,
KE = 0.5mv²
Equating the kinetic energies before and after collision,
0.5(60)(8 m/s)² = (0.5)(60)(x²) + (0.5)(0.45)(35 m/s)²
The value of x from the equation is approximately 7.40 m/s
Yes I'm pretty sure you can
Answer: ro= 0.113
Explanation:
Data Given: Where D= Outer diameter
d= Inner diameter
ri= 0.4cm
r°= ?
Charge 1 and Charge 2 (q) = K i.e constant of proportionality
Where K = 1/4πe°. er; 3.2, ep; 2.6 ( Relative permeability)
(a) Approximate value size for the coaxial cable
C= 7.354 x Er/ Log 10 (D÷d)
C = 7.354 x 3.2/ Log 2.6
= 23.5/0.419
= 56.0cm
(b) Outer radius r° when dealing with 20kv
r°= impedance value (pie ÷ 20) d^2
r° = 2( π÷20)0.6^2
= 2( 0.1571) 0.36
r° = 0.113
(c) Assuming The Maximum Electric Field; Fmax = 25%
Given Vin = 25x10^6v/m, Vout = 20x 10^6 v/m.
Impedance p= √Vin x vout/ Z° (i)
Where Z° = electric surge ~25%
Subtituting Value of Vin & Vout In Equation (i)
P = 2.05x10^-8ohms
Note : Length of a conducting material determines the strength of dielectric material between the coaxial cable
Answer:
No you would not be an entrepreneur
Explanation:
An entrepreneur is someone who creates a business, and also organize the business affairs. The entrepreneur takes on the biggest financial risk.