<span>1/5(2x-15) + (3/5)x = 4 1/4
</span><span>x*2/5 - 15/5 + x*3/5 = 4 1/4
</span><span>x*2/5 - 3 + x*3/5 = 4 1/4
</span><span>x*(2/5+3/5) - 3 = 4 1/4
</span><span>x*(5/5) - 3 = 4 1/4
</span>1*x - 3 = 4 1/4
<span>x= 4 1/4 + 3
</span><span>x= 7 1/4 </span>
There are 18 coins total in her bag:
7+3+8=18coins
3 of the 18 coins are dimes, so the odds of first drawing a dime are 3/18
P(dime)=3/18
Since the nickel was taken out and not replaced, there are now 17 coins in her purse.
18-1=17coins
8 of the 17 remaining coins are nickels, so the odds of drawing a nickel are 8/17.
P(nickel)=8/17
Now we multiply the two probabilities by eachother to find out the odds of both occurring...
P(dime)*P(nickel)=
3/18*8/17=24/306=8/103=0.078=8%
The probability of grabbing a dime and then a nickel are 8/103 or 0.078 or an 8% chance, whichever way you'd prefer to write it.
Answer:
2a +b =5
Step-by-step explanation:
4a + 2b = 10
Divide each side by 2
4a/2 +2b/2 = 10/2
2a +b =5
<span>36 divided by .40 = 90 so its 90
</span>
<span>2 + 13x, because (19x − 6x) + 2 = 13x + 2 = 2 + 13x</span>
