Answer:
First 1-5 in pics
I can't upload further reactions
Explanation:
- sandmeyer's reaction
- swarts reaction
- Finkelstein reaction
- wurtz reaction
- reimer teimann reaction
6. Lucas test
ROH + Zncl2 +HCl ---> RCl + H2O
7. esterification
R-OH +R’-COOH +H+↔ R’-COOR
<u>Answer:</u> The amount of oxygen gas consumed is 0.525 moles
<u>Explanation:</u>
We are given:
Moles of propane burned = 0.150 moles
The chemical equation for the combustion of propane follows:

By Stoichiometry of the reaction:
1 mole of propane reacts with 5 moles of oxygen gas
So, 0.150 moles of propane will react with =
of oxygen gas
Hence, the amount of oxygen gas consumed is 0.525 moles
Answer: 1. 1.59 x 10^23 Particles
2. 4.79 x 10^21 particles
3. 2.67 x 10^25 particles
4. 2.12 x 10^23 Particles
Explanation: 1mole of any substance contains 6.02x10^23 Particles
1. 0.264 mol of silver will contain = 0.264 x 6.02x10^23 = 1.59 x 10^23 Particles
2. 7.95 x 10^-3 mol sodium chloride will contain = 7.95 x 10^-3 X 6.02x10^23 = 4.79 x 10^21 particles
3. 44.4 mol carbon dioxide will contain = 44.4 x 6.02x10^23 = 2.67 x 10^25 particles
4. 0.352 mol nitrogen will contain = 0.352 x 6.02x10^23 = 2.12 x 10^23 Particles
Answer:
At the end of second half life 12.5 g will left
Explanation:
Given data:
Total Mass = 50 g
Half lives = 2
Mass remain at the end = ?
Solution:
At time zero = 50 g
At 1st half life = 50 g /2 = 25 g
At second half life = 25 g/2 = 12.5 g
So at the end of second half life 12.5 g will left.
The minimum energy required to remove an electron from a potassium metal can be obtained by subtracting the energy of the incident photons from the kinetic energy of the removed photoelectrons. Based from the given values, the following equation is obtained:
Minimum energy required = 4.23×10^-19 J - <span>1.864×10^-21 J
</span>
We then get 4.2114 x 10^-19 J as the minimum energy required to remove the electron. We then convert this into units of energy per mole. This is to be done by using Avogadro's number which result to the following equation:
Minimum energy required per mole = 4.2114 x 10^-19 J x 6.022 x 10^23 mol^-1
The final answer is then 253.608 kJ/mol