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Molodets [167]
3 years ago
14

Consider four atoms from the second period: lithium, beryllium boron carbon and nitrogen which of these element has the lowest e

lectronegativity value?
Chemistry
2 answers:
LiRa [457]3 years ago
6 0

Answer is: lithium.

Electronegativity (χ) is a property that describes the tendency of an atom to attract a shared pair of electrons.

Electronegativity increases from left to right across a period.  

Atoms with higher electronegativity attracts more electrons towards it, electrons are closer to that atom.

For example nitrogen has electronegativity approximately χ = 3 and lithium has χ = 1, so if they form bond, nitrogen will have negative and lithium positive charge.

bearhunter [10]3 years ago
5 0
Lithium has the lowest. if fluorine is the highest then lithium is the lowest. i hope this helps you out!
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maks197457 [2]

Answer:

First 1-5 in pics

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Explanation:

  1. sandmeyer's reaction
  2. swarts reaction
  3. Finkelstein reaction
  4. wurtz reaction
  5. reimer teimann reaction

6. Lucas test

ROH + Zncl2 +HCl ---> RCl + H2O

7. esterification

R-OH +R’-COOH +H+↔ R’-COOR

3 0
2 years ago
When 0.105 mol propane, C3H8 is burned in an excess of oxygen, how many moles of oxygen are consumed? The products are carbon di
torisob [31]

<u>Answer:</u> The amount of oxygen gas consumed is 0.525 moles

<u>Explanation:</u>

We are given:

Moles of propane burned = 0.150 moles

The chemical equation for the combustion of propane follows:

C_3H_8+5O_2\rightarrow 3CO_2+4H_2O

By Stoichiometry of the reaction:

1 mole of propane reacts with 5 moles of oxygen gas

So, 0.150 moles of propane will react with = \frac{5}{1}\times 0.105=0.525mol of oxygen gas

Hence, the amount of oxygen gas consumed is 0.525 moles

6 0
3 years ago
Determine the number of representative particles in each of the following.
klio [65]

Answer: 1. 1.59 x 10^23 Particles

2. 4.79 x 10^21 particles

3. 2.67 x 10^25 particles

4. 2.12 x 10^23 Particles

Explanation: 1mole of any substance contains 6.02x10^23 Particles

1. 0.264 mol of silver will contain = 0.264 x 6.02x10^23 = 1.59 x 10^23 Particles

2. 7.95 x 10^-3 mol sodium chloride will contain = 7.95 x 10^-3 X 6.02x10^23 = 4.79 x 10^21 particles

3. 44.4 mol carbon dioxide will contain = 44.4 x 6.02x10^23 = 2.67 x 10^25 particles

4. 0.352 mol nitrogen will contain = 0.352 x 6.02x10^23 = 2.12 x 10^23 Particles

4 0
3 years ago
A 50 gram sample of a radioisotope undergoes 2 half-lives. How many grams
Veseljchak [2.6K]

Answer:

At the end of second half life 12.5 g will left

Explanation:

Given data:

Total Mass = 50 g

Half lives = 2

Mass remain at the end = ?

Solution:

At time zero = 50 g

At 1st half life = 50 g /2 = 25 g

At second half life = 25 g/2 = 12.5 g

So at the end of second half life 12.5 g will left.

3 0
3 years ago
Photoelectrons are removed with kinetic energy 1.864×10^-21 J, when photons of light with energy 4.23×10^-19 J fall on the metal
tensa zangetsu [6.8K]
The minimum energy required to remove an electron from a potassium metal can be obtained by subtracting the energy of the incident photons from the kinetic energy of the removed photoelectrons. Based from the given values, the following equation is obtained:

Minimum energy required = 4.23×10^-19 J - <span>1.864×10^-21 J
</span>
We then get 4.2114 x 10^-19 J as the minimum energy required to remove the electron. We then convert this into units of energy per mole. This is to be done by using Avogadro's number which result to the following equation:

Minimum energy required per mole = 4.2114 x 10^-19 J x 6.022 x 10^23 mol^-1

The final answer is then 253.608 kJ/mol
6 0
3 years ago
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