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miskamm [114]
3 years ago
11

An ionic bond always forms between ___ ion with a positive charge and ___ ion with a negative charge. This is not a multiple cho

ice question.
Chemistry
1 answer:
barxatty [35]3 years ago
7 0
Cation is positive and anion is negative
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What mass of magnesium hydroxide is required to create a 441 mL solution with a pH of 12.52?
marshall27 [118]

Answer:

0.423g

Explanation:

akording to mass = concetration x volume

4 0
3 years ago
1. Classify each of the following as a homogeneous or heterogeneous substance.
Olegator [25]

a. iron ore  - heterogeneous substance

(it contains a mixture of iron oxides)

b. quartz  - homogeneous substance

(it is the crystalline silicon dioxide SiO₂, which is a very pure form of SiO₂)

c. granite  - heterogeneous substance

(it as mixture of different oxides, mainly aluminium and silicon oxides)

d. energy drink  - heterogeneous substance

(a mixture of water, sugar, carbon dioxide and different substances that may boost concentration, like caffeine)

e. oil-and-vinegar salad dressing  - heterogeneous substance

(this salad dressing of oil and vinegar is composed of unsaturated triglycerides, acetic acid and water)

f. salt  - homogeneous substance

(sodium chloride NaCl)

g. rainwater  - homogeneous substance

(assuming the the atmosphere is clean, it is just pure water H₂O)

h. nitrogen - homogeneous substance

(it is the main component of air and it is a diatomic molecule N₂)

7 0
3 years ago
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In an accident, a solution containing 2.5 kg of nitric acid was spilled. Two kilograms of Na2CO3 was quickly spread on the area
storchak [24]

First we must write a balanced chemical equation for this reaction

Na_2CO_3 _(_a_q_)+ 2HNO_3_(_a_q_) \implies 2NaNO_3_(_s_) + CO_2_(_g_) + H_2O_(_l_)

The mole ratio for the reaction between HNO_3 and Na_2CO_3 is 1:2. This means 1 moles of Na_2CO_3 will neutralize 2 moles HNO_3. Now we find the moles of each reactant based on the mass and molar mass.

2500g HNO_3 \times \frac{mol}{63.01g\ HNO_3} = 39.67 mol\ HNO_3

2000g\ Na_2CO_3 \times \frac{mol}{105.99g \ Na_2CO_3} = 18.87 mol\ Na_2CO_3

\frac{18.87 mol Na_2CO_3}{39.67\ HNO_3} = \frac{1 molNa_2CO_3}{2 mol HNO_3}

The Na_2CO_3 was enough to neutralize the acid because 18.87:39.67 is the same as 1:2 mol ratio.

4 0
3 years ago
How many moles of Al will be consumed when 0.400 mol of Al2O3 are produced in
Vladimir [108]

Answer:

C) 0.800 mol

Explanation:

  • 4Al + 3O₂ → 2Al₂O₃

In order to <u>convert from moles of Al₂O₃ into moles of Al</u>, we'll need to use<em> the stoichiometric coefficients</em>, using a conversion factor that has Al₂O₃ moles in the denominator and Al moles in the numerator:

  • 0.400 mol Al₂O₃ * \frac{4molAl}{2molAl_2O_3} = 0.800 mol Al

So the correct answer is option C).

7 0
2 years ago
Why are animal vaccinated?
juin [17]

Answer:

to go against dangerous viral and bacteria

Explanation:

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