Balanced Half reactions are:
At anode 2
==> Cl₂+ 
+ H₂O ==> 
+ 2
+
At Cathode: 2 + ==> H₂
Since the question states that you are using an aqueous solution of MnCl₂, so ions will have present are, H₂O, , 
and
Now at Anode reaction will occur as given:
2 ==> Cl₂+ + H₂O ==> + 2 + (will occur)
At Cathode:
2 + ==> H₂ (will occur)
At Cathode:
+ ==> Mn (This reaction will not occur)
The deposition of solid Mn will not occur because in aqueous solution, will be reduced before .
The reduction potentials for is zero whereas reduction potential for is - 1.18V.
The reduction potential of a species is its tendency to gain electrons and get reduced. It is measured in millivolts or volts. Larger positive values of reduction potential are indicative of a greater tendency to get reduced.
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Answer:
D no. is the answer of your question
The balanced chemcial equation is B. So to do single, we need to look at where would Li stand on the metals chart (For my class we have a chart to see which element is the highest on the metals chart) . So since Li is higher, F needs to go with Li, leaving Ba alone.
I hope this helps you!
If the graph shows that the energy increases as the reaction proceeds, this means that the state of the reaction of the compounds A, B, C and D is exothermic because the system releases heat to the surroundings, thus, resulting to the increase in energy involved in the reaction.
Metamorphism would compare to a mineral that formed through evaporation
