Solve for x PLEASE HELP

what is the altitude corresponding to the side of length 8.5 CM in a parallelogram whose area is 34 CM square

Crazy boy [7]

Area = length of base × altitude
34 = 8.5 × a
34 = 8.5a
a = 34/8.5
a = 4

The altitude of the corresponding side is 4 cm

4 0

3 years ago

The perimeter of a rectangular field is 60ft and its width is 20ft find the area of this field

Gennadij [26K]

Perimeter of rectangle = 2( length +width)

given: Perimeter=60 ft and width=20 ft

plugging these values in the formula,

60=2(20+ length)

dividing both sides by 2

30=20+length

length =30-20=10

length is 10 feet

width is 20 feet

Area of rectangle is given by:

Area = l*w

Area = 10 *20 = 200 square feet

Answer : Area of rectangle is 200 square feet.

4 0

4 years ago

Read 2 more answers

A paper store sells wrapping paper rolls and bags. In the spring, they order a ratio of 3:7 in wrapping paper bags in the spring

Maru [420]

If it can be assumed that the total number paper and bags is the same for both orders, then:

#bags ordered in the spring=7*(150/3)=350, so the total of both is 150+350=500. A 5:5 ratio means that the wrapping paper and bags were bout in equal quantities. That means 500/2=250 for each.

6 0

3 years ago

Please help, as soon as possible...

vodomira [7]

Answer:

1. a) Square

2. c) Rectangle

Step-by-step explanation:

1. If you cut this rectangular prism in way to be PERPENDICULAR to the base, that means you're cutting it straight down, from the top to the bottom, in a vertical line. The cross-section obtained will be just like an end of the prism, which in this case is a square. Because it's a regular rectangular prism, no matter where you cut it, as long as it's vertical, perpendicular to the base, you'll get a square due to this particular form. Technically, the answer could also be a rectangle, since a square is a rectangle.

2. you cut this rectangular prism in way to be PARALLEL to the base, that means you're cutting it straight, from the front to the back, in an horizontal line. The cross-section obtained will be just like an top of the prism, which in this case is a rectangle. Because it's a regular rectangular prism, no matter where you cut it, as long as it's an horizontal line, parallel to the base, you'll get a rectangle due to this particular form.

6 0

3 years ago

The process standard deviation is 0.27, and the process control is set at plus or minus one standard deviation. Units with weigh

mr_godi [17]

Answer:

a) $P(X$

And for the other case:

tex] P(X>10.15)[/tex]

$P(X>10.15)= P(Z > \frac{10.15-10}{0.15}) = P(Z>1)=1-P(Z$

So then the probability of being defective P(D) is given by:

$P(D) = 0.159+0.159 = 0.318$

And the expected number of defective in a sample of 1000 units are:

$X= 0.318*1000= 318$

b) $P(X$

And for the other case:

tex] P(X>10.15)[/tex]

$P(X>10.15)= P(Z > \frac{10.15-10}{0.05}) = P(Z>3)=1-P(Z$

So then the probability of being defective P(D) is given by:

$P(D) = 0.00135+0.00135 = 0.0027$

And the expected number of defective in a sample of 1000 units are:

$X= 0.0027*1000= 2.7$

c) For this case the advantage is that we have less items that will be classified as defective

Step-by-step explanation:

Assuming this complete question: "Motorola used the normal distribution to determine the probability of defects and the number of defects expected in a production process. Assume a production process produces items with a mean weight of 10 ounces. Calculate the probability of a defect and the expected number of defects for a 1000-unit production run in the following situation.

Part a

The process standard deviation is .15, and the process control is set at plus or minus one standard deviation. Units with weights less than 9.85 or greater than 10.15 ounces will be classified as defects."

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

$X \sim N(10,0.15)$

Where $\mu=10$ and $\sigma=0.15$

We can calculate the probability of being defective like this:

$P(X$

And we can use the z score formula given by:

$z=\frac{x-\mu}{\sigma}$

And if we replace we got:

$P(X$

And for the other case:

tex] P(X>10.15)[/tex]

$P(X>10.15)= P(Z > \frac{10.15-10}{0.15}) = P(Z>1)=1-P(Z$

So then the probability of being defective P(D) is given by:

$P(D) = 0.159+0.159 = 0.318$

And the expected number of defective in a sample of 1000 units are:

$X= 0.318*1000= 318$

Part b

Through process design improvements, the process standard deviation can be reduced to .05. Assume the process control remains the same, with weights less than 9.85 or greater than 10.15 ounces being classified as defects.

$P(X$

And for the other case:

tex] P(X>10.15)[/tex]

$P(X>10.15)= P(Z > \frac{10.15-10}{0.05}) = P(Z>3)=1-P(Z$

So then the probability of being defective P(D) is given by:

$P(D) = 0.00135+0.00135 = 0.0027$

And the expected number of defective in a sample of 1000 units are:

$X= 0.0027*1000= 2.7$

Part c What is the advantage of reducing process variation, thereby causing process control limits to be at a greater number of standard deviations from the mean?

For this case the advantage is that we have less items that will be classified as defective

5 0

3 years ago