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3 years ago

How did mendel use his training in mathematics to aid his experiments in life science?

1 answer:

3 0

Mendel use his training in mathematics to aid his experiments in life science by using it for the offspring sexual reproduction. He mainly studied pea plants because they had distinguished characteristics and they were quick to grow. Mendel would create hybrids from the plants.

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Methylamine (ch3nh2) is a weak base. at equilibrium, which expression equals the base dissociation constant (kb) of methylamine?

Molodets [167]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

Below are the choices that can be found elsewhere:

a. [CH3NH-] * [OH-] / [CH3NH3+]
b. [CH3NH3+] / ([CH3NH2] * [OH-]) 
c. [CH3NH3+] * [OH-] / [CH3NH2] 
d. [CH3NH3+] * [OH-] / [CH3NH2] * [H2O]

The answer is C.

4 0

3 years ago

**25 POINTS**. I doubt anyone will do this but it's worth a try to ask. To do this exercise, you will need fifteen containers, f

Travka [436]

Answer:

done not that hard

Explanation:

6 0

3 years ago

Where are the most reactive metals located?

Lapatulllka [165]

Answer:

option B = lower left of the periodic table

Explanation:

The most reactive metals are located at the bottom left corner of periodic table. These metals are reactive in the sense that they can react with water very easily.

Examples include lithium, sodium potassium. As we move down the group in this column metallic character increase. Their atomic radius also increases and electron can easily donated. which means metals became more reactive.

These metals can also react very easily with O2 in atmosphere that's way these are stored in inert atmosphere. The most reactive metal in periodic table is francium.

7 0

3 years ago

Read 2 more answers

What is the empirical formula of a vanadium (i) oxide given that 20.38 grams of vanadium combines with oxygen to form 23.58 gram

oksano4ka [1.4K]

V₂O is the empirical formula of a vanadium (i) oxide given that 20.38 grams of vanadium combines with oxygen to form 23.58 grams of the oxide.

The simplest whole number ratio of the atoms of the elements in a specific compound is shown by the empirical formula for that compound. When the mass of each component of a compound or its % composition by mass is known, an empirical formula may typically be computed.

% composition is equal to (mass of an element minus mass of the compound) / 100%.

Given

Vanadium weighs 20.38 g.

The oxide's mass is 23.58 g.

% Vanadium composition: (20.38 g/23.58 g) 100%

= 86.43%

Oxygen mass equals 23.58 g minus 20.38 g

= 3.2 g

100% of oxygen's composition is (3.2/g/23.58 g)

= 13.57%

Atomic mass and number are related by composition percentage.

Vanadium's atomic weight is 50.94 g/mol.

Atomic weight of V = 86.43 / 50.94

= 1.6967

Oxygen has an atomic mass of 16 g/mol.

O atom count is 13.57/16.

= 0.8481

Now on calculation the ratio of Vanadium to the oxygen is

1.6967/0.8481 = 2/1

Ratio of whole numbers is 2:1

Thus V₂O is the empirical formula .

Learn more about empirical formula here brainly.com/question/13058832

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6 0

1 year ago

draw the organic product (if any) expected from the following reaction CH3CH2CH2OH + K2Cr2O7(aq) ---->H2SO4 is catalystNote:

m_a_m_a [10]

Answer:

The product will be propanoic acid .

Explanation:

Under the action of strong oxidizing agent that is potassium dichromate in an acidic medium primary oxidizes the primary alcohols into carboxylic acid .

$RCH_2OH+K_2Cr_2O_7\overset{H^+}\rightarrow RCOOH+H_2O$

So, when propanol is treated with potassium dichromate in an acidic medium it get converted into propanoic acid.

$CH_3-CH_2-CH_2-OH+K_2Cr_2O_7\overset{H^+}\rightarrow CH_3-CH_2-COOH+H_2O$

6 0

3 years ago