Ask question

Ask question

All categories

2 years ago

13

Determine (a) the starting height, (b) the time to hit the ground, and (c) the velocity when it hits the ground for an object sh

ot horizontally with a speed of 8 m/s that lands 10 m away.

1 answer:

Salsk061 [2.6K]2 years ago

8 0

Answer:

a

Explanation:

You might be interested in

An electric dipole of dipole moment 'p' is placed in the position of stable equilibrium in a uniform field of intensity 'E'. The

larisa86 [58]

Answer:

Torque by electric dipole = pEcos thita

5 0

3 years ago

What words does convection come from

ludmilkaskok [199]

Answer:

from Late Latin convectionem

Explanation:

6 0

2 years ago

If a woman weighs 125 lb, her mass expressed in kilograms is x kg, where x is

adelina 88 [10]

The first thing you should know to solve this problem is the conversion of pounds to kilograms:
1lb = 0.45 Kg
We can solve this problem by a simple rule of three
1lb ---> 0.45Kg
125lb ---> x
Clearing x we have:
x = ((125) / (1)) * (0.45) = 56.25 Kg.
Answer
her mass expressed in kilograms is 56.25 Kg.

3 0

2 years ago

Read 2 more answers

The temperature of a body falls from 30°C to 20°C in 5 minutes. The air

natulia [17]

Answer:

15.88°C I am not 100% sure this is right but I am 98% sure this IS right

7 0

2 years ago

On a snowy day, max (mass = 15 kg) pulls his little sister maya in a sled (combined mass = 20 kg) through the slippery snow. max

sesenic [268]

Work done by a given force is given by

$W = F.d$

here on sled two forces will do work

1. Applied force by Max

2. Frictional force due to ground

Now by force diagram of sled we can see the angle of force and displacement

work done by Max = $W_1 = Fdcos\theta$

$W_1 = 12*5cos15$

$W_1 = 57.96 J$

Now similarly work done by frictional force

$W_2 = Fdcos\theta$

$W_2 = 4*5cos180$

$W_2= -20 J$

Now total work done on sled

$W_{net}= W_1 + W2$

$W_{net} = 57.96 - 20 = 37.96 J$

7 0

3 years ago