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Gre4nikov [31]
3 years ago
15

A body is dropped from a height H. In how much time will it reach the ground?

Physics
1 answer:
Maslowich3 years ago
5 0

Answer:

s = ut +  \frac{1}{2} g {t}^{2}  \\ t(u +  \frac{1}{2} gt) = H \\ u +  \frac{1}{2} gt = H \\ t = 2(H - u) \div g \\ t =  \frac{(H - u)}{5}  \\ u \: is \: speed \: or \: velocity

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7 0
4 years ago
a force 2.4E2 N exists between a positive charge of 8E-5 C and a positive charge of 3E-5 C. What distance separates the charges?
Verdich [7]

The distance between the two charges is 0.3 m

Explanation:

The electrostatic force between two charged objects is given by Coulomb's law:

F=k\frac{q_1 q_2}{r^2}

where:

k=8.99\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

q_1, q_2 are the charges of the two objects

r is the separation between the two charges

In this problem, we are given the following:

q_1 = 8\cdot 10^{-5} C

q_2 = 3\cdot 10^{-5} C

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Therefore, we can rearrange the equation to solve for r, the distance between the two charges:

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Learn more about electrostatic force:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

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