<u>Answer:</u> The average atomic mass of element bromine is 80.4104 amu.
<u>Explanation:</u>
Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.
Formula used to calculate average atomic mass follows:
.....(1)
- <u>For _{35}^{79}\textrm{Br}[/tex] isotope:</u>
Mass of 
isotope = 78.9183 amu
Percentage abundance of isotope = 50.69 %
Fractional abundance of isotope = 0.5069
- <u>For
isotope:</u>
Mass of isotope = 80.9163 amu
Percentage abundance of isotope = 49.31 %
Fractional abundance of isotope = 0.4931
Putting values in equation 1, we get:
![\text{Average atomic mass of Bromine}=[(78.9183\times 0.5069)+(80.9163\times 0.4931)]](https://tex.z-dn.net/?f=%5Ctext%7BAverage%20atomic%20mass%20of%20Bromine%7D%3D%5B%2878.9183%5Ctimes%200.5069%29%2B%2880.9163%5Ctimes%200.4931%29%5D)
Hence, the average atomic mass of element bromine is 80.4104 amu.
False, there are five forms of matter; solid, liquid, glass, plasma, and <span>Bose-Einstein condensates.
hope this helps :)</span>
If the liquid is at or above its flash point, the flame spread rate is fast, and the entire pool is engulfed within seconds. ... As the liquid temperature decreases, flame radiation must both heat the liquid to the flash point temperature and supply the heat of vaporization.
Answer:
23430.4 J.
Explanation:
From the question given above, the following data were obtained:
Mass (M) = 70 g
Initial temperature (T₁) = 10 °C
Final temperature (T₂) = 90 °C
Specific heat capacity (C) = 4.184 J/gºC
Heat (Q) required =?
Next, we shall determine the change in the temperature of water. This can be obtained as follow:
Initial temperature (T₁) = 10 °C
Final temperature (T₂) = 90 °C
Change in temperature (ΔT) =?
ΔT = T₂ – T₁
ΔT = 90 – 10
ΔT = 80 °C
Finally, we shall determine the heat energy required to heat up the water. This can be obtained as follow:
Mass (M) = 70 g
Change in temperature (ΔT) = 80 °C
Specific heat capacity (C) = 4.184 J/gºC
Heat (Q) required =?
Q = MCΔT
Q = 70 × 4.184 × 80
Q = 23430.4 J
Therefore, 23430.4 J of heat energy is required to heat up the water.
Answer:
This is because no energy is being created or destroyed in this system
Explanation:
I think this is correct? I hope it helps.
