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Tom [10]
2 years ago
14

2 H2(g) + O2(g) 2 H2000

Chemistry
1 answer:
guajiro [1.7K]2 years ago
4 0
A. 2 x 3 = 6 mol H2O
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A student observes two strips of magnesium, mg ribbon that are each 3cm long. One strip of magnesium
ankoles [38]

Therefore option c , i.e. The substances in both test tubes are reactive only at high temperatures. is the only statement which is NOT supported by the student's observations.

<h3>What is the reaction between Magnesium and Hydrogen ?</h3>

Magnesium reacts with hydrochloric acid to produce hydrogen gas

Mg (s) + 2 HCl (aq) → MgCl₂ (aq) + H₂ (g)

In this reaction, the magnesium and acid are gradually used up , which can be seen in the test tube 2 .

A chemical reaction is taking place in Test tube 2 ,

Hydrogen gas is released in test tube 2 ,

Energy is released in the reaction involving hydrochloric acid and we can see in test tube 2 the reaction is going on

therefore option C i.e. The substances in both test tubes are reactive only at high temperatures. is the only statement which is NOT supported by the student's observation.

To know more about the chemical reaction between Magnesium and Hydrogen and this test.

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6 0
2 years ago
Lonic Bonding
oksano4ka [1.4K]
Na has a +1 charge, and O has a -1 charge.
3 0
3 years ago
What is the dropped down number in a chemical formula that tells the number of atoms of a particular element? *
densk [106]
The lack of a number preceding the carbon symbol C and the compound formula CO2 shows that there is one carbon atom and one carbon dioxide molecule. Subscript numbers in chemical formulas represent the number of atoms or molecules immediately preceding the subscript.
3 0
3 years ago
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Calculate the work (kJ) done during a reaction in which the internal volume contracts from 85 L to 12 L against an outside press
butalik [34]

Answer:

The work done on the system is 17.75_KJ

Explanation:

To solve this question we need to know the required equations from the given variables, thus

Initial volume = 85L

Final volume = 12L

External pressure = 2.4 atm.

work done = - PΔV

2.4×(85-12) = 175.2L×atm

Converting from L•atm to KJ is given by

1 L•atm = 0.1013 kJ

(175.2 L•atm) * (0.1013 kJ / 1 L•atm)

= 17.75 kJ

The work done on the system is 17.75_KJ

5 0
3 years ago
Please help me I need this
klio [65]
It would be:
1.D
2.A
3.B
4.C

7 0
3 years ago
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