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Charra [1.4K]
3 years ago
5

1. Suppose a 10 N force is applied to the side of a 4.0 kg block that is sitting on a table what would be the minimum value of t

he coefficient of static friction in order for the block to remain motionless?
Physics
1 answer:
vlada-n [284]3 years ago
3 0

Answer:

\mu= 0.25

Explanation:

Given data

Force= 10N

mass= 4kg

r= 4*9.81

r= 39.24N

The expression for the force acting is expressed as

F=\mu*r

substitute

\mu=F/r

\mu= 10/39.24

\mu= 0.25

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Possibly, if you have list of densities and you have to match it. I can't think of any other scenarios in which it would be able to.

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7 0
3 years ago
Why should we change away from using incandescent light bulbs
Maurinko [17]

They are energy inefficient

Explanation:

The main reason why we must change away from using incandescent lighting bulbs is because of their energy inefficiency.

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8 0
3 years ago
A rectangular copper strip 1.5cm wide and 0.10cn thick carries a current of 5.0A. Find the Hall voltage for a 1.2T magnetic fiel
Scrat [10]

Answer:

4.4345× 10^-7V

Explanation:

The computation of the half voltage for a 1.2T magnetic field applied is shown below

The volume of one mole of copper is

v = m ÷p

= 63.5 ÷ 8.92

= 7.12cm

Now the density of free electrons in copper is

n = Na ÷ V

= 6.02 × 10^23 ÷ 7.12

= 8.456× 10^28/m^3

Now the half voltage is

= IB ÷ nqt

= (5 × 1.20) ÷ (8.456× 10^28 × 1.6 × 10^-19 × 0.1× 10^-2)

= 4.4345× 10^-7V

7 0
3 years ago
What is the momentum of a two-particle system
Harlamova29_29 [7]

Answer:

-67,500 kgm/s

Explanation:

1300 * 20 + 1100 * (-85) = -67,500 kgm/s

8 0
3 years ago
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Answer:

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Explanation:

6 0
3 years ago
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