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Charra [1.4K]
3 years ago
5

1. Suppose a 10 N force is applied to the side of a 4.0 kg block that is sitting on a table what would be the minimum value of t

he coefficient of static friction in order for the block to remain motionless?
Physics
1 answer:
vlada-n [284]3 years ago
3 0

Answer:

\mu= 0.25

Explanation:

Given data

Force= 10N

mass= 4kg

r= 4*9.81

r= 39.24N

The expression for the force acting is expressed as

F=\mu*r

substitute

\mu=F/r

\mu= 10/39.24

\mu= 0.25

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