We know average speed =total distance/time taken
So avg speed=(85+63)/(5+5)=14.8km/hr
Position 1 I believe because that is when the potential energy is released on the downfall
Answer:
x = 1.00486 m
Explanation:
The complete question is:
" The potential energy between two atoms in a particular molecule has the form U(x) =(2.6)/x^8 −(5.1)/x^4 where the units of x are length and the num- bers 2.6 and 5.1 have appropriate units so that U(x) has units of energy. What is the equilibrium separation of the atoms (that is the distance at which the force between the atoms is zero)? "
Solution:
- The correlation between force F and energy U is given as:
F = - dU / dx
F = - d[(2.6)/x^8 −(5.1)/x^4] / dx
F = 20.8 / x^9 - 20.4 / x^5
- The equilibrium separation distance between atoms is given when Force F is zero:
0 = 20.8 / x^9 - 20.4 / x^5
0 = 20.8 - 20.4*x^4
x^4 = 20.8/20.4
x = ( 20.8/20.4 )^0.25
x = 1.00486 m
Answer:
The Ring of Fire
Explanation:
The ring of fire is also called the Circum-Pacific Belt, it is a path along the pacific ocean consisting of active volcanoes and frequent earthquakes.
It has a length of approximately 40,000 kilometers. It lies on the edge of tectonic plates where the in-earth vibrations and geothermal energies are prone to erupt out.
Ring of fire inhibits about 75% o the earth's volcanoes and 95% of earthquakes occur in this region.
Answer:
v₁ = -0.8087 m / s
Explanation:
To solve this problem we can use the conservation of momentum, for this we define a system formed by the man, the skateboard and the brick, therefore the force during the separation is internal and the momentum is conserved
Initial instant. When they are united
p₀ = 0
Final moment. After throwing the brick
= (m_man + m_skate) v1 + m_brick v2
the moment is preserved
p₀ = p_{f}
0 = (m_man + m_skate) v₁ + m_brick v₂
v₁ = - 
the negative sign indicates that the two speeds are in the opposite direction
let's calculate
v₁ = - 
v₁ = -0.8087 m / s
