3 years ago

Please help this is confusing !

Mathematics

1 answer:

WINSTONCH [101]3 years ago

3 0

Answer:

-1, 0

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

Help plz im so bad at math

pantera1 [17]

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3 years ago

Find the value of each of these quantities. <br> C(5,3)<br> C(8,8)<br> C(12,6)

Paul [167]

$C^n_k= \frac{n!}{(n-k)!c!} 
\\
\\C^5_3= \frac{5!}{(5-3)!3!} = \frac{5!}{2!3!} = \frac{5\times4\times3}{3\times2\times1} =10
\\
\\C^8_8= \frac{8!}{(8-8)!8!} = \frac{8!}{0!8!} = \frac{8!}{1\times8!}=1
\\
\\C^{12}_6= \frac{12!}{(12-6)!6!} = \frac{12!}{6!6!} = \frac{12\times11\times10\times9\times8\times7}{6\times5\times4\times3\times2\times1} =\frac{11\times3\times4\times7}{1} =924$