Answer:
The transverse wave will travel with a speed of 25.5 m/s along the cable.
Explanation:
let T = 2.96×10^4 N be the tension in in the steel cable, ρ = 7860 kg/m^3 is the density of the steel and A = 4.49×10^-3 m^2 be the cross-sectional area of the cable.
then, if V is the volume of the cable:
ρ = m/V
m = ρ×V
but V = A×L , where L is the length of the cable.
m = ρ×(A×L)
m/L = ρ×A
then the speed of the wave in the cable is given by:
v = √(T×L/m)
= √(T/A×ρ)
= √[2.96×10^4/(4.49×10^-3×7860)]
= 25.5 m/s
Therefore, the transverse wave will travel with a speed of 25.5 m/s along the cable.
Answer:2. The number of miles driven and the amount of gas used.
Explanation:
If it takes ten minutes to travel 5 km, then it'll take 60 minutes to travel thirty, making your biking speed 30 kilometers per hour. 25 minutes divided by ten is 2.5. multiply 5 by 2.5 to get 12.5, your average walking speed.
Answer:

Explanation:
As we know that box was initially at rest
so here work done by all forces on the box = change in its kinetic energy
so we will have

now we have
m = 10 kg

L = 3.5 m
so we will have


so final speed is given as
