Ask question

Ask question

All categories

2 years ago

15

What type of circuit is illustrated?A)closed series circuit

2 answers:

antoniya [11.8K]2 years ago

6 0

Answer:

the correct awnser is closed sereis circuit i just took the test and chose his awnser and it was wrong THE CORRECT AWNSER IS A

Explanation:

RoseWind [281]2 years ago

4 0

I think it’s B open series circuit but I’m not sure

You might be interested in

Where an electric field line crosses an equipotential surface, the angle between the field line and the equipotential is

n200080 [17]

Answer:

90 degree

Explanation:

Electric field line is vertical to the electric field line.

4 0

2 years ago

An electric current flows through a parallel circuit. Which units tell you about the amount of electrons traveling in the circui

kompoz [17]

'Ampere' is the unit of current. That's the rate at which
electrons travel in the circuit ... the number of electrons
every second. If you wanted the actual amount or number
of electrons, you'd need to know the length of time too.

It doesn't matter whether we're talking about a parallel or
series circuit.

8 0

3 years ago

A point charge of 6.0 nC is placed at the center of a hollow spherical conductor (inner radius = 1.0 cm, outer radius = 2.0 cm)

egoroff_w [7]

Explanation:

The given data is as follows.

q = 6.0 nC = $6 \times 10^{-9} C$

inner radius (r) = 1.0 cm = 0.01 m (as 1 cm = 100 m)

So, there will be same charge on the inner surface as the charge enclosed with an opposite sign.

Formula to calculate the charge density is as follows.

$\sigma = \frac{q_{in}}{A}$ .......... (1)

Since, area of the sphere is as follows.

A = $4 \pi r^{2}$ ........... (2)

Hence, substituting equation (2) in equation (1) as follows.

$\sigma = \frac{q_{in}}{4 \pi r^{2}}$

= $\frac{6 \times 10^{-9} C}{4 \times 3.14 \times (0.01)^{2}}$

= $0.477 \times 10^{-5}$

or, = 4.77 $\mu C/m^{2}$

Thus, we can conclude that the resulting charge density on the inner surface of the conducting sphere is 4.77 $\mu C/m^{2}$ .

5 0

2 years ago

According to Wien's Law, how many times hotter is an object whose blackbody emission spectrum peaks in the blue, at a wave lengt

scZoUnD [109]

Answer:1.55 times

Explanation:

Given

First wavelength $(\lambda _1)=450 nm$

Second wavelength $(\lambda _2)=700 nm$

According wien's diplacement law

$\lambda T=constant$

where $\lambda =wavelength$

T=Temperature

Let $T_1 and T_2$ be the temperatures corresponding to $\lambda _1 & \lambda _2$ respectively.

$\lambda _1\times T_1=\lambda _2\times T_2$

$\frac{T_1}{T_2}=\frac{\lambda _2}{\lambda _1}$

$\frac{T_1}{T_2}=\frac{700}{450}=1.55$

Thus object with $\lambda 450 nm$ is 1.55 times hotter than object with wavelength $\lambda =700 nm$

8 0

3 years ago

Explain why a Chef in a very busy restaurant would prefer a copper pot over an aluminum pot. A) The copper pot would heat faster

stellarik [79]

A would be the answer

5 0

2 years ago

Read 2 more answers