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asambeis [7]
3 years ago
14

A transformer changes the 10,000 v power line to 120 v. if the primary coil contains 750 turns, how many turns are on the second

ary?
Physics
1 answer:
inn [45]3 years ago
5 0
For a transformer, the ratio between the number of turns of primary and secondary coil is the same as the ratio between the voltages on the two coils:
\frac{N_p}{N_s}= \frac{V_p}{V_s}
Where N_p and N_s are the number of turns in the primary and secondary coils, while V_p and V_s are the voltages on the two coils.

Using the data of the problem: N_p=750, V_p=10000 V and V_s=120 V, we can find N_s, the number of turns of the secondary coil:
N_s=N_p  \frac{V_s}{V_p}=750  \frac{120 V}{10000 V}=9
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A ball is thrown upward. At a height of 10 meters above the ground, the ball has a potential energy of 50 joules (with the poten
lions [1.4K]

Answer:

 h = 20 m

Explanation:

given.

height, h = 10 m

Potential energy at 10 m = 50 J

Kinetic energy at 10 m = 50 J

maximum height the ball will reach, H = ?

Total energy of the system

T E = 50 J + 50 J

T E = 100 J

now,

A h = 10 m

P E = m g h

50 = m g x 10

mg = 5 ..............(1)

at the top most Point the only Potential energy will be acting on the body.

now, TE = Potential energy

 100 = m g h

5 h = 100

 h = 20 m

hence, the maximum height reached by the ball is equal to 20 m.

5 0
3 years ago
the specific heat of gold is 0.031 calories degrees Celsius and the specific heat of silver is 0.057 calories degrees Celsius so
givi [52]

Answer:

Explanation:

Given:

Specific heat of gold  = 0.031cal/°C

Specific heat of silver  = 0.057cal/°C

To know the metals that will heat up faster, we must understand the meaning of specific heat capacity.

It is the amount of heat required to raise the temperature of 1g of a substance by 1°C.

Now,

The higher the specific heat capacity the more energy it is required to heat up the substance.

So, Gold with a specific heat capacity of 0.031cal/°C  will heat up faster.

8 0
2 years ago
A heat engine operating between energy reservoirs at 20?c and 600?c has 30% of the maximum possible efficiency.
Anarel [89]
 <span>The maximum possible efficiency, i.e the efficiency of a Carnot engine , is give by the ratio of the absolute temperatures of hot and cold reservoir. 
η_max = 1 - (T_c/T_h) 

For this engine: 
η_max = 1 - [ (20 +273)K/(600 + 273)K ] = 0.66 = 66% 

The actual efficiency of the engine is 30%, i.e. 
η = 0.3 ∙ 0.664 = 0.20 = 20 % 

On the other hand thermal efficiency is defined as the ratio of work done to the amount of heat absorbed from hot reservoir: 
η = W/Q_h 

So the heat required from hot reservoir is: 
Q_h = W/η = 1000J / 0.20 = 5000J</span>
8 0
3 years ago
Describe the motion of an unanchored rowboat when a water wave passes
USPshnik [31]
It mimics the movement of the waves 
6 0
3 years ago
Read 2 more answers
Suppose you are measuring double‑slit interference patterns using an optics kit that contains the following options that you can
svetlana [45]

Answer:

3.6 m

Explanation:

\lambda_R = 650 \ nm\\\\\lambda_R = 650*10^{-9} m\\\\L \ should \ be \ minimum \\\\i.e \  0.25 \ mm\\\\= 0.25 *10^{-3} m

\lambda_R = 700 \ nm\\\\\lambda_R = 700*10^{-9} m\\\\

Also

\beta = 1 \ mm \ fringe \  width

D_{min} = \frac{\beta d}{\lambda}\\\\D_{min} = \frac{10^{-3}*0.25*10^{-3}}{700*10^{-9}}\\\\D_{min} = 3.57 \\D_{min} =  3.6 m

Therefore, the minimum distance L  you can place a screen from the double slit that will give you an interference pattern on the screen that you can accurately measure using an ordinary 30 cm (12 in) ruler. = 3.6 m

4 0
3 years ago
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