Mr. Mole's burrow was at an altitude of 6 meters below the ground.
Step-by-step explanation:
Step 1:
We need to determine the distance that Mr. Mole covers in a single minute.
To do that we divide the difference in values of altitude by the difference in the time periods.
For the first case, Mr. Mole had traveled -18 meters in 5 minutes.
We also have, he traveled -25.2 meters in 8 minutes.
Step 2:
The distance he covered in 1 minute 
So with every minute, Mr. Mole digs down an additional 2.4 meters below the surface.
To determine where Mr. Mole's burrow is we subtract the distance traveled in 5 minutes from -18.
The altitude of Mr. Mole's burrow 
So Mr. Mole's burrow was at an altitude of 6 meters below the ground i.e. -6 meters.
The answer to this is .5 or 1/2.
Answer:
C a1= -2
an = an-1 +3
Step-by-step explanation:
an = -2+ (n-1)3
What is the first term? Let n=1
a1 = -2 + 0*3
a1 = -2
The difference between the terms is +3 (coefficient on (n-1))
The second term is the first term +3
The third term is the second term plus 3
The next term is the previous term +3
so an = an-1+ 3
Answer:
The correct option is (A).
Step-by-step explanation:
The equation for the Estimated Energy Requirement (EER) of 19 or more years older men is:
Here,
AGE = age counted in years
PA = appropriate physical activity factor
WT = weight in kilograms
HT = height in meters
The physical activity factor for men and women is:
Activity Level PA (men) PA (Women)
Sedentary 1.00 1.00
Low 1.11 1.12
Active 1.25 1.27
Very Active 1.48 1.45
Given:
AGE = 22 year-old male college student
PA = low = 1.11
WT = 180 pounds = 81.6466 kg
HT = 5'10" = 1.778 m
Compute the value of EER as follows:
Thus, the EER for a 22-year-old male college student is approximately 2962 kcal.
The correct option is (A).
The answer is 19 packages of popsicles. You would multiply 19 and 3 and get 57. After you get 57 you subtract 3 and end up with 54
