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Tom [10]
3 years ago
15

What is the weight of a pumpkin with a mass of 5 kg? kk

Physics
1 answer:
pav-90 [236]3 years ago
4 0

Explanation:

actually, the question would need to give you what is the gravitational force, so let's take the average of the gravitational for me which is 10 N /kg

and the formula for finding weight is

W = mg

W = (5)(10)

W = 50 N

hope it is helpful, if not please report it so that someone else gets to try

please vote

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Air resistance is a nonconservative force. It always opposes the motion of an object. An airplane flies from New York to Atlanta
LenKa [72]

Answer:

c) is negative

Explanation:

As we know that work done by a force is the product of force and displacement vector.

W= F.d

F= Force

d= displacement

The work done by friction force always negative because it try to oppose the motion and act opposite to the direction of displacement.So the work done by air resistance is negative.

c) is negative

8 0
3 years ago
A nonconducting sphere is made of two layers. The innermost section has a radius of 6.0 cm and a uniform charge density of −5.0C
Leno4ka [110]

Answer:

a) E =0, b)   E = 1,129 10¹⁰ N / C , c)    E = 3.33 10¹⁰ N / C

Explanation:

To solve this exercise we can use Gauss's law

        Ф = ∫ E. dA = q_{int} / ε₀

Where we must define a Gaussian surface that is this case is a sphere; the electric field lines are radial and parallel to the radii of the spheres, so the scalar product is reduced to the algebraic product.

           E A = q_{int} /ε₀

The area of ​​a sphere is

          A = 4π r²

         E = q_{int} / 4πε₀ r²

         k = 1 / 4πε₀

         E = k q_{int} / r²

To find the charge inside the surface we can use the concept of density

        ρ = q_{int} / V ’

         q_{int} = ρ V ’

         V ’= 4/3 π r’³

Where V ’is the volume of the sphere inside the Gaussian surface

 Let's apply this expression to our problem

a) The electric field in center r = 0

     Since there is no charge inside, the field must be zero

          E = 0

b) for the radius of r = 6.0 cm

In this case the charge inside corresponds to the inner sphere

        q_{int} = 5.0  4/3 π 0.06³

         q_{int} = 4.52 10⁻³ C

        E = 8.99 10⁹  4.52 10⁻³ / 0.06²

         E = 1,129 10¹⁰ N / C

c) The electric field for r = 12 cm = 0.12 m

In this case the two spheres have the charge inside the Gaussian surface, for which we must calculate the net charge.

     The charge of the inner sphere is q₁ = - 4.52 10⁻³ C

The charge for the outermost sphere is

       q₂ =  ρ 4/3 π r₂³

       q₂ = 8.0 4/3 π 0.12³

       q₂ = 5.79 10⁻² C

The net charge is

     q_{int} = q₁ + q₂

     q_{int} = -4.52 10⁻³ + 5.79 10⁻²

     q_{int} = 0.05338 C

The electric field is

        E = 8.99 10⁹ 0.05338 / 0.12²

        E = 3.33 10¹⁰ N / C

8 0
3 years ago
Please help asap!!!!
Lady bird [3.3K]

Answer:

4 is the answer

Explanation:

hope this helps

7 0
3 years ago
Is the force of the mosquito on the car larger than, smaller than, or equal to the force of the car on the mosquito?
Goshia [24]
Equal to, mosquitos are in no way compared to a the force of a vehicle
7 0
3 years ago
Read 2 more answers
An automobile travels on a straight road for 40 km at 30 km/h. It then continues in the same direction for another 40 km at 60 k
Butoxors [25]

Answer:

The average velocity is 40km/h.

Explanation:

The average velocity is \bar{v}=\frac{\Delta x }{\Delta t}, where \Delta x is the distance traveled and \Delta t the time elapsed.

The distance traveled is clearly 80km since it's all done in the same direction, we only need to know the time elapsed. For this we calculate the time elapsed on the first part, and add it to the time elapsed on the second part using always the formula \Delta t=\frac{\Delta x }{v}, where v is the velocity on each part, which is constant.

The time elapsed for the first part is \Delta t_1=\frac{40 km}{30km/h}=\frac{4}{3}h, and the time elapsed for the second part is \Delta t_2=\frac{40 km}{60km/h}=\frac{2}{3}h, giving us a total time of \Delta t_1+\Delta t_2=\frac{4}{3}h+\frac{2}{3}h=2h.

Finally, we can calculate the average velocity: \bar{v}=\frac{80km}{2h}=40km/h.

6 0
3 years ago
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