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dimulka [17.4K]
2 years ago
10

What is deceleration?????Have a nice day​

Physics
2 answers:
const2013 [10]2 years ago
6 0

Answer:

\deceleration)

Explanation:

<h2>DEÇELERATIØÑ ALWAYS REFERs TØ ACCELERATION IN THE DIRECTION ØPPOSITE TO THE DIRECTION OF VILØÇÏTY <em><u>.</u></em></h2>

<h3><em><u>DEÇELERATIØÑ</u></em><em><u> </u></em><em><u>ALWAYS</u></em><em><u> </u></em><em><u>reduces</u></em><em><u> </u></em><em><u>speed</u></em><em><u> </u></em><em><u>.</u></em></h3>

<em><u>✌️</u></em><em><u>ur</u></em><em><u> answer</u></em><em><u> hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u> you</u></em><em><u> ✌️</u></em>

Rufina [12.5K]2 years ago
3 0
Deceleration—the ability to slow down and control force production—is often ignored during training; but deceleration technique is critical for most sports. Speed is often the factor that separates the elite from the average athlete. Credit source is stack.com have a nice day! I told you it was from the internet in case you couldn’t use the internet Hope this helped :)!
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Which answer choice provides the best set of labels for Wave A and Wave B?
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A has less energy and lower frequency, while B has greater energy and higher frequency.
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3 years ago
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What potential difference is needed to give a helium nucleus (q=2e) 85.0 kev of kinetic energy?
Vilka [71]
The kinetic energy K given to the helium nucleus is equal to its potential energy, which is 
E=q \Delta V
where q=2e is the charge of the helium nucleus, and \Delta V is the potential difference applied to it.
Since we know the kinetic energy, we have
E=K=85~keV=q \Delta V
and from this we can find the potential difference:
\Delta V =  \frac{K}{q}= \frac{85~keV}{2e}=42.5~kV

6 0
2 years ago
A ______________ is very general in nature, while a ________________ specifies what we want to study more specifically, suggesti
vova2212 [387]

Answer:

research topic and research question (hypothesis)

Explanation:

6 0
3 years ago
g a small smetal sphere, carrying a net charge is held stationarry. what is the speed are 0.4 m apart
Veseljchak [2.6K]

Answer:

The speed of q₂ is 4\sqrt{10}\ m/s

Explanation:

Given that,

Distance = 0.4 m apart

Suppose, A small metal sphere, carrying a net charge q₁ = −2μC, is held in a stationary position by insulating supports. A second small metal sphere, with a net charge of q₂ = −8μC and mass 1.50g, is projected toward q₁. When the two spheres are 0.800m apart, q₂ is moving toward q₁ with speed 20m/s.

We need to calculate the speed of q₂

Using conservation of energy

E_{i}=E_{f}

\dfrac{1}{2}mv_{i}^2+\dfrac{kq_{1}q_{2}}{r_{i}}=\dfrac{kq_{1}q_{2}}{r_{f}}+\dfrac{1}{2}mv_{f}^2

\dfrac{1}{2}m(v_{i}^2-v_{f}^2)=kq_{1}q_{2}(\dfrac{1}{r_{f}}-\dfrac{1}{r_{i}})

Put the value into the formula

\dfrac{1}{2}\times1.5\times10^{-3}(20^2-v_{f}^2)=9\times10^{9}\times-2\times10^{-6}\times-8\times10^{-6}(\dfrac{1}{(0.4)}-\dfrac{1}{(0.8)})

0.00075(400-v_{f}^2)=0.18&#10;

400-v_{f}^2=\dfrac{0.18}{0.00075}

-v_{f}^2=240-400

v_{f}^2=160

v_{f}=4\sqrt{10}\ m/s

Hence, The speed of q₂ is 4\sqrt{10}\ m/s

7 0
2 years ago
A car accelerates from rest to 19 m/s in 6 seconds. What is the acceleration of the car?
choli [55]

Answer:

the car is moving so that how it gos so fast

Explanation:

7 0
3 years ago
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