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1 year ago

Are bonds broken or formed, throughout each phase change present on a heating curve?

Chemistry

1 answer:

Blababa [14]1 year ago

5 0

Answer:

During a phase change no chemical bonds are broken. Atoms are not rearranged because a phase change is a physical change rather then a chemical change. However, intermolecular forces are almost entirely removed from the liquid since the intermolecular forces are what cause the liquid to be a liquid.

Explanation:the nature of the intermolecular forces (IMF) will not change when the state changes from solid to liquid, however, the number of IMF changes.

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How does the number of valence electrons determine the type and number of bonds an element forms?

Advocard [28]

The number of electrons in an atom's outermost valence shell governs its bonding behaviour. Elements whose atoms have the same number of valence electrons are grouped together in the Periodic Table. ... Nonmetals tend to attract additional valence electrons to form either ionic or covalent bonds.

8 0

2 years ago

Why do thermistors increase in conductivity when heated? What happens in normal metals? Explain on the atomic level.

Marysya12 [62]

Metal conductivity generally goes down or resistivity goes up with temperature goes up.

7 0

1 year ago

How many grams of oxygen gas will be produced when 2.50 moles of potassium chlorate is decomposed?

yawa3891 [41]

Answer:

$m_{O_2}=120gO_2$

Explanation:

Hello!

In this case, since the decomposition of potassium chlorate is:

$2KClO_3\rightarrow 2KCl+3O_2$

We can see a 2:3 mole ratio between potassium chlorate and oxygen (molar mass 32.0 g/mol), thus, via stoichiometry, we compute the mass of oxygen that are produced by the decomposition of 2.50 moles of this reactant:

$m_{O_2}=2.50molKClO_3*\frac{3molO_2}{2molKClO_3} *\frac{32.0gO_2}{1molO_2}\\\\m_{O_2}=120gO_2$

Best regards!

8 0

2 years ago

A certain metal M crystallizes in a lattice described by a body-centered cubic (bcc) unit cell. The lattice constant (a, the edg

Furkat [3]

Answer:

radius = 156 pm

Explanation:

The relation between radius and edge length of unit cell of BCC is

r=a $\sqrt{3}$ /4

Given

a = 360 pm

Therefore

r = r = radius = 360 $\sqrt{3}$ /4= 155.88 pm

156 pm

3 0

2 years ago

In a redox reaction, the substance that accepts electrons is said to be

brilliants [131]

The substance doesn't have a specific name. We just say that that substance is being reduced. Remember this mnemonic - OILRIG where "Oxidation is Loss, Reduction is Gain" of electrons.

3 0

2 years ago