Answer:
thermoforming
Explanation:
please mark this answer as the brainlest
Explanation:
D the answer is D and anyone can answer this Question
Answer:
i) 796.18 N/mm^2
ii) 1111.11 N/mm^2
Explanation:
Initial diameter ( D ) = 12 mm
Gage Length = 50 mm
maximum load ( P ) = 90 KN
Fractures at = 70 KN
minimum diameter at fracture = 10mm
<u>Calculate the engineering stress at Maximum load and the True fracture stress</u>
<em>i) Engineering stress at maximum load = P/ A </em>
= P / 
= 90 * 10^3 / ( 3.14 * 12^2 ) / 4
= 90,000 / 113.04 = 796.18 N/mm^2
<em>ii) True Fracture stress = P/A </em>
= 90 * 10^3 / ( 3.24 * 10^2) / 4
= 90000 / 81 = 1111.11 N/mm^2
Answer:
10 ft or 3.048 m (for unqualified person)
1.09 ft or 0.33 m (for qualified person)
Explanation:
OSHA has prescribed "Minimum Approach Distance - MAD" to ensure safety of personnel working with electrical power lines.
For a unqualified person:
The minimum approach distance is 10 ft or 3.048 m
For a qualified person:
For a voltage in the range of 300V to 750V (Phase to Ground or Phase to Phase) the minimum approach distance is 1.09 ft or 0.33 m
Since 600V lies in the above range hence it is applicable on 600V.
OSHA has developed a full list of minimum approach distance according to the level of voltages (50V to 72000V)
