Answer:
The heat transfer q = 18.32W
Explanation:
In this question, we are asked to calculate the heat entering the tube and also evaluate properties at T =400K
Please check attachment for complete solution and step by step explanation
It is desired to produce and aligned carbon fiber-epoxy matrix composite having a longitudinal tensile strength of 800 MPa. Calc
1 answer:
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Answer:
a) Decrease
b) Decrease
c) Decrease
d) Decrease
Explanation:
Ti= 200°F ,
Te = 170°F
Area of heat exchanger = = 20π
<u>A) when The flow rate of the cooling fluid is increased</u>
Temperature of process stream will decrease and this is because the tube side heat transfer coefficient will increase and this will increase the rate of heat transfer thereby decreasing the temperature of the process stream.
B) <u>when There are 200 tubes that are 1.0-in. OD and 20.0ft long</u>
The temperature of the process stream will decrease and this is because the heat transfer coefficient will increase likewise the heat transfer rate
C) <u>When The number of shell passes is doubled</u>
This will cause an increase in the overall length of the shell, an increase in velocity of constant volumetric flowrate, hence the Temperature of the process steam will decrease as well
D)<u> When The tube material is changed to copper.</u>
Due to the high thermal conductivity of copper when compared to steel , switching to copper will cause a decrease in the temperature of the process steam
Answer:
The true stress necessary to plastically elongate the specimen is 406.69MPa
Explanation:
The Explanation or Solving is on the attached document.
Answer:
a) the coefficient of performance of the air conditioner is 3.5729
b)
- the power input required for a reversible air conditioner is 0.645 hp
- the coefficient of performance for the reversible air conditioner is 18.2759
Explanation:
Given the data in the question;
Lower Temperature = 70°F = ( 70 + 460 )R = 530 R
Higher Temperature = 99° F = ( 99 + 460 )R = 559 R
Cooling Load = 30000 Btu/h
we know that 1 hp = 2544.43 Btu/h
Net power input P = 3.3 hp = ( 3.3 × 2544.43 )Btu/h = 8396.619 Btu/h
a)
Coefficient of performance of the air conditioner;
= Cooling Load
/ power P
we substitute
= 30000 Btu/h / 8396.619 Btu/h
= 3.5729
Therefore, the coefficient of performance of the air conditioner is 3.5729
b)
- Power input required ( in hp )
/
=
/ (
-
)
we substitute
30000 Btu/h / = 530 R / ( 559 R - 530 R )
30000 Btu/h / = 530 R / 29 R
we solve for
= ( 30000 Btu/h × 29 R ) / 530 R
= ( 870000 Btu/h / 530 )
= 1641.5094 Btu/h
we know that; 1 hp = 2544.43 Btu/h
so;
= ( 1641.5094 / 2544.43 ) hp
= 0.645 hp
Hence, the power input required for a reversible air conditioner is 0.645 hp
- the coefficient of performance for the reversible air conditioner;
=
/ (
-
)
we substitute
= 530 R / ( 559 R - 530 R )
= 530 R / 29 R
= 18.2759
Hence, the coefficient of performance for the reversible air conditioner is 18.2759