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stealth61 [152]
3 years ago
7

describe the coordinate system that is usually chosen for analyzing circular motion and state at least one advantages for this c

hoice.
Physics
1 answer:
Darina [25.2K]3 years ago
4 0
The circular motion is usually analyzed by using the polar coordinates (\rho, \theta). The transformation between Cartesian coordinates (x,y) and polar coordinates is
x= \rho cos \theta
y= \rho \sin \theta
where basically \rho corresponds to the distance between the object and the origin of the axes (0,0) while \theta is the angle which gives the direction.

The main advantage of the polar coordinates is that when analyzing a circular motion, the radius \rho is a constant, since the object is moving on a circular path, and so it is possible to describe the motion of the object by specifying only the angle \theta.
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Which ONE of the following pairs of physical quantities consists of one scalar and one vector quantity?
lyudmila [28]

Answer:

speed and acceleration

Explanation:

speed is a scalar quantity

acceleration is a vector quantity

7 0
2 years ago
CAN SOMEONE PLEASE ANSWER NUMBER 10 FOR ME WITH AN EXPLANATION HURRY I HAVE LIMITED TIME PLEASE!!!
lara31 [8.8K]
Answer: B

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4 0
3 years ago
A baseball fan is 150.0 m from the home plate. how much time elapses between the instant the fan sees the batter hit the ball an
Artyom0805 [142]

Approximately 0.4373 seconds

Speed of sound at 20 degree C is roughly 343 meters/second

Speed of light = 3x10^8 or 300,000,000 meters/second

at 150.0 feet away you set it up as:

150.0/343 - 150/3x10^8

150.0/343 = 0.43731778

150/3x10^8 = 5x10^-7 or 0.0000005

Subtract 0.43731778 - 0.0000005

Answer is 0.43731728

Rounding would be approx. 0.4373

7 0
3 years ago
The copper wire and bulb is connected in a series with 220 V electric supply. Why only an electric bulb glows where as the coppe
Sveta_85 [38]
-- In a series circuit, the current ( I ) is the same at every point.

-- The power dissipated by any section of the circuit is I² x Resistance.

-- The wire has very low resistance, so I²R is very low dissipated power.

-- The filament in the bulb has most all of the resistance in the circuit,
so it dissipates virtually all the power of the circuit, and certainly much
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7 0
3 years ago
2. A certain object revolves at a rate of 30 rpm. Please determine the frequency and period of this
schepotkina [342]

Answer:

The time period of the motion is, T = 0.03 s

The frequency of the rotation is, f = 30 Hz

Explanation:

Given data,

The rotational speed of an object, ω = 30 rpm

                                                          ω = 188.5 rad/s

The time period of motion is,

                            T = 2π / ω

Substituting the given values in the above equation

                               = 2π / 188.5

                            T = 0.03 s

The time period of the motion is, T = 0.03 s

The frequency of rotation,

                                f = 1 /T

                                   = 1 / 0.03

                                   = 30 Hz

Hence, the frequency of the rotation is, f = 30 Hz

7 0
3 years ago
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