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3 years ago

7

Nitrogen gas at standard atmospheric pressure 101.3 kPa, has a volume of 0.080 m3. If there are 3.6 mol of the gas, what is the

temperature?

1 answer:

marysya [2.9K]3 years ago

6 0

Answer:

271 K

Explanation:

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stiks02 [169]

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Explanation:

We are given that

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$v_x=v_0cos\theta=v_0cos35$

$v_y=v_0sin\theta=v_0sin35$

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$1.8=v_0sin35\frac{30}{v_0cos35}-\frac{1}{2}(9.8)(\frac{30}{v_0cso35})^2$

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$v^2_0=\frac{6574.6}{19.2}$

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Initial velocity of the ball=18.5 m/s

b.Substitute the value then we get

$t=\frac{30}{18.5cos35}$

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