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sashaice [31]
3 years ago
14

A little girl riding a train rolls a ball toward the back of the train at 1.25 m/s NE. The train is traveling at a velocity of 1

3.22 m/s SW. The little girl's brother runs from the back of the train, toward the rolling ball at a velocity of 1.45 m/s SW. Relative to the little girl's brother, what is the velocity of the rolling ball?
Physics
1 answer:
Lelechka [254]3 years ago
4 0

Answer:

Answer: 2.70m/s NE

Explanation:

Just did it.

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A ball has a mass of 1.5kg and is thrown straight up with a speed of 60m/s, what is the ball’s momentum:
madam [21]

Answer:

Assumption: the air resistance on this ball is negligible. Take g = 10\; \rm m \cdot s^{-2}.

a. The momentum of the ball would be approximately 60\;\rm kg \cdot m \cdot s^{-1} two seconds after it is tossed into the air.

b. The momentum of the ball would be approximately \rm \left(-45\; \rm kg \cdot m \cdot s^{-1}\right) three seconds after it reaches the highest point (assuming that it didn't hit the ground.) This momentum is smaller than zero because it points downwards.

Explanation:

The momentum p of an object is equal its mass m times its velocity v. That is: \vec{p} = m \cdot \vec{v}.

Assume that the air resistance on this ball is negligible. If that's the case, then the ball would accelerate downwards towards the ground at a constant g \approx -10\; \rm m \cdot s^{-2}. In other words, its velocity would become approximately 10\; \rm m \cdot s^{-1} more negative every second.

The initial velocity of the ball is 60\; \rm m \cdot s^{-1}. After two seconds, its velocity would have become 60\;\rm m \cdot s^{-1} + 2\; \rm s \times \left(-10\;\rm m \cdot s^{-1}\right) = 40\; \rm m \cdot s^{-1}. The momentum of the ball at that time would be around p = m \cdot v \approx 60\; \rm kg \cdot m \cdot s^{-1}.

When the ball is at the highest point of its trajectory, the velocity of the ball would be zero. However, the ball would continue to accelerate downwards towards the ground at a constant g \approx -10\; \rm m \cdot s^{-2}. That's how the ball's velocity becomes negative.

After three more seconds, the velocity of the ball would be 0\; \rm m \cdot s^{-1} + 3\; \rm s \times \left(-10\; \rm m \cdot s^{-2}\right) = -30 \; \rm m \cdot s^{-1}. Accordingly, the ball's momentum at that moment would be p = m \cdot v \approx \left(-45\; \rm kg \cdot m \cdot s^{-1}\right).

3 0
3 years ago
Explanation for x=73km/h•0.5s= 10.14 pls help how did they get 10.14? What was the work around it
Sergio [31]
Hi I am the guy to get mad at
4 0
2 years ago
If a dog runs 25m east and then turns around and runs
Nostrana [21]

Answer:

The dog ran a total distance of 45m but he is only 5m away from the starting line

Explanation: When you add 25 to 20 you get 45 for the total distance and if he ran back in the same direction then you would subtract 20 from 25 and get 5m

8 0
3 years ago
A force is applied to a 30-kg object, resulting in an acceleration of 15 m/s. What is the force being applied to the object?
telo118 [61]
The sum of all forces applied to the object = (mass) x (acceleration)

The sum of all forces applied to the object = (30) x (15)

= <u>450 newtons</u>, in the direction of the acceleration.
 
5 0
3 years ago
Read 2 more answers
Non-living factors in an ecosystem are<br><br> biotic<br><br> abiotic<br><br> antibiotic
zaharov [31]

Answer:

Abiotic

Explanation:

The non living factors of the ecosystem which is essential for the survival of living factors of the ecosystem are abiotic factors.

Examples for abiotic factors include temperature, sunlight, water, wind etc....

3 0
3 years ago
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